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valina [46]
2 years ago
13

When you serve the ball, if the ball does not land in the opposite side rectangle this is called a ______. question 2 options: f

ault miss volley foul
Physics
1 answer:
Novay_Z [31]2 years ago
4 0

Answer:

its called a fault

Explanation:

Its when u mess up

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What is 6.9 × 107 written in standard form?
n200080 [17]
Answer: 6.9x 107 in standard form is 69,000,000

7 0
2 years ago
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a linear function has the same y-intercept as x + 4y equals 16 and it's graph contains the point (4,5). Find the slope of the li
navik [9.2K]

Answer:  \bold{\text{Slope (m)}=\dfrac{1}{4}}

<u>Explanation:</u>

A linear equation is of the form: y = mx + b   where

  • m is the slope
  • b is the y-intercept (where it crosses the y-axis)

x + 4y = 16

     4y = -x + 16

       y = -\dfrac{1}{4}x+\dfrac{16}{4}

       y=-\dfrac{1}{4}x+4

The y-intercept (b) = 4

Next, find the slope given point (4, 5) and b = 4

y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}

6 0
3 years ago
Can a solution be separated by filtration?​
alexgriva [62]

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

Listo!

8 0
3 years ago
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Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c
rodikova [14]

Answer:

Pressure of woman will be 99.87\times 10^5N/m^2

Pressure of the elephant will be 1716560.50N/m^2

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity g=9.8m/sec^2

Diameter of shoes = 1 cm =0.01 m

So radius r=\frac{d}{2}=\frac{0.01}{2}=0.005m

So area A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2

We know that force is given  F = mg

So F=80\times 9.8=784N

Now we know that pressure is given by P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be A=3.14\times 0.1^2=0.0314m^2

So pressure will be P=\frac{53900}{0.0314}=1716560.50N/m^2

3 0
3 years ago
A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t
Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = \sqrt{\frac{k}{m} }

k is spring constant and m is mass attached

ω = \sqrt{\frac{20}{1.5} }

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0
3 years ago
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