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2 years ago

13

When you serve the ball, if the ball does not land in the opposite side rectangle this is called a ______. question 2 options: f

ault miss volley foul

1 answer:

Novay_Z [31]2 years ago

4 0

Answer:

its called a fault

Explanation:

Its when u mess up

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What is 6.9 × 107 written in standard form?

n200080 [17]

Answer: 6.9x 107 in standard form is 69,000,000

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2 years ago

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a linear function has the same y-intercept as x + 4y equals 16 and it's graph contains the point (4,5). Find the slope of the li

navik [9.2K]

Answer: $\bold{\text{Slope (m)}=\dfrac{1}{4}}$

<u>Explanation:</u>

A linear equation is of the form: y = mx + b where

m is the slope
b is the y-intercept (where it crosses the y-axis)

x + 4y = 16

4y = -x + 16

$y = -\dfrac{1}{4}x+\dfrac{16}{4}$

$y=-\dfrac{1}{4}x+4$

The y-intercept (b) = 4

Next, find the slope given point (4, 5) and b = 4

$y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}$

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3 years ago

Can a solution be separated by filtration?

alexgriva [62]

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

Listo!

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3 years ago

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Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c

rodikova [14]

Answer:

Pressure of woman will be $99.87\times 10^5N/m^2$

Pressure of the elephant will be $1716560.50N/m^2$

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity $g=9.8m/sec^2$

Diameter of shoes = 1 cm =0.01 m

So radius $r=\frac{d}{2}=\frac{0.01}{2}=0.005m$

So area $A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2$

We know that force is given F = mg

So $F=80\times 9.8=784N$

Now we know that pressure is given by $P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2$

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be $A=3.14\times 0.1^2=0.0314m^2$

So pressure will be $P=\frac{53900}{0.0314}=1716560.50N/m^2$

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3 years ago

A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t

Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = $\sqrt{\frac{k}{m} }$

k is spring constant and m is mass attached

ω = $\sqrt{\frac{20}{1.5} }$

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0

3 years ago