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ICE Princess25 [194]
3 years ago
10

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled roc

ks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? ​
Chemistry
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

the answer is petroleum

Explanation:

This is because they need a bigger drill to get to it. They also need to go down to the level oil is found.

i hope this helps

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Calculate the amount of F.A.S required to prepare 1000 ml of 0.1 molar standard solution of F.A.S
RideAnS [48]

Answer:

Preparation and Standardization of 0.1 M Ferrous Ammonium...

Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.

Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.

Standardize the solution in the following manner.

Explanation:

8 0
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Complete the analogy solid:Table:.......water​
prisoha [69]

Answer:

of

Explanation:

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At this temperature, 0.300 mol H 2 0.300 mol H2 and 0.300 mol I 2 0.300 mol I2 were placed in a 1.00 L container to react. What
Alekssandra [29.7K]

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The concentration of HI present at equilibrium is 0.471 M.

Explanation:

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A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H₂O
ollegr [7]

Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.381g

Mass of H_2O=0.692g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, \frac{2}{18}\times 0.692=0.0769g of hydrogen will be contained.

Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

This means that there is no other element present in the compound.

3 0
3 years ago
Why can't astronomers take a picture of a black hole?
san4es73 [151]

Answer:

Gravity is so strong that even light cannot escape a black hole.

Explanation:

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3 years ago
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