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kogti [31]
3 years ago
12

An ionic bond is a bond that forms between.. help

Chemistry
2 answers:
JulsSmile [24]3 years ago
5 0

Answer:

ions with opposite charge

Explanation:

ionic bond is formed between oppositely charged ions in a chemical compound.

MA_775_DIABLO [31]3 years ago
3 0

Answer: ions with opposite charges

Explanation:

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34. Given the fact that the concentrations of reactants and
Nina [5.8K]

Answer:

The word dynamic is used to describe chemical equilibrium because even though the concentration of reactants and products remains constant, the reaction does not stop, but still continues with the rate of forward reaction equal to the rate of backward reaction. This is opposed to static equilibrium where there is no reaction at all.

Hope this helps you out!

3 0
3 years ago
Using 273.15 K as the value for Zero degree Celsius convert 45.1° C to Kelvin. 6.05 K 318 K 318.3 K 1.23 x 104 K
OLEGan [10]
Zero degree celcius = 273.15 degree kelvin

Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).

Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin

Approximating to the nearest tenth, the value will be 318.3 degree kelvin
8 0
3 years ago
HELP! will mark brainliest if gotten right
Lorico [155]
The answer is B i think
5 0
3 years ago
Can someone help me? It needs to have a diagram that has arrows.
daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)

The expression for enthalpy change is,

\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]

Putting the values we get :

\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]

-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]

H_f_{C_4H_{10}=-125kJ/mol

Thus enthalpy change for formation of butane is -125 kJ/mol

5 0
3 years ago
When making calculations, you should rely on the precision of your measured data.
ELEN [110]
True 

Im happy i could help you today 

have a great rest of ur week :)
3 0
3 years ago
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