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statuscvo [17]
3 years ago
4

Which expression is equivalent to 12x − 8x + 3 and why? (1 point) 3 + 4x, because (12x − 8x) + 3 = 4x + 3 = 3 + 4x 7x, because 1

2x − 8x + 3 = 4x + 3 = 7x 12x − 5, because 12x − (8x − 3) = 12x − 5 x, because 12x − 8x + 3 = 12x − 11x = x
Physics
1 answer:
IgorLugansk [536]3 years ago
8 0

3 + 4x, because (12x − 8x) + 3 = 4x + 3 = 3 + 4x

Explanation:

The equivalent expression to 12x - 8x + 3 is 3 + 4x

         Expression 12x -8x +3;

x is a variable whose value is unknown in the given equation.

                           12x  - 8x + 3

Let us solve and simplify the equation above:

                        (12x-8x) + 3;

                            4x + 3;

                 This is the same as 3 + 4x

Learn more:

Equivalent expression brainly.com/question/11207748

#learnwithBrainly

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Copper is commonly used as an effective conductor in household appliances and in electrical equipment in general. Because of its low cost, most wires are copper-plated. You will often find electromagnet cores normally wrapped with copper wire

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El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
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Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

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pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

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3 0
3 years ago
A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe
marin [14]

Answer:

a) T_f=305.7049\ K

b) \Delta S=313.51\ J.K^{-1}

Explanation:

Given:

  • mass of copper, m_c=2.64\ kg
  • initial temperature of copper, T_{ic}=400\ K
  • specific heat capacity of copper, c_c=385\ J.kg^{-1}.K^{-1}
  • mass of water, m_w=4\ kg
  • initial temperature of water, T_{iw}=300\ K
  • specific heat capacity of water, c_w=4200\ J.kg^{-1}.K^{-1}

a)

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)

T_f=305.7049\ K

b)

<u>Now the amount of heat transfer:</u>

Q=m_c.c_c.(T_{ic}-T_{f})

Q=2.64\times 385\times (400-305.7049)

Q=95841.5841\ J

∴Entropy change

\Delta S=\frac{dQ}{T}

\Delta S=\frac{95841.5841}{305.7049}

\Delta S=313.51\ J.K^{-1}

5 0
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