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Roman55 [17]
3 years ago
15

Kia is doing an experiment in science lab. She is given a beaker containing 100 g of liquid. The beaker has markings on the side

for measuring volume. The water comes up to the 100 mL mark. Kia puts the liquid on a hot plate by mistake. By the time she realizes the mistake, half of her liquid has evaporated.
Kia still needs 100 g of liquid for her experiment. To find out how much liquid she has to replace, she needs to re-weigh her liquid. However, the balance she used before is now broken. The teacher tells Kia that she can tell how much water is left by looking. The water now comes up to the 50 mL mark.

How much mass does Kia's remaining water have?
Physics
1 answer:
lozanna [386]3 years ago
7 0
Kia's remaining water has a mass of 50g. You can set it up as a proportion knowing that 100ml of water has a mass of 100g and thus 50ml of water would weight 50g
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What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?
Alchen [17]

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

  • When a simple pendulum swings back and forth, it has some energy associated with its motion.
  • The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
  • The potential energy of the simple pendulum is given by P.E = mgh
  • The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
  • When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
  • When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
  • Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.
8 0
4 years ago
Ohms law in symbols is
serious [3.7K]

Answer:

The potential difference across a given given wire of an circuit is directly proportional to the current flowing through it provided it's temperature remains the same. This is known as ohm's law

V is proportional to I

V/I = constant

V/I = R

V = IR where R is the constant of proportionality and resistance of the wire

Hope this helps!

6 0
3 years ago
Which of the waves has the smallest amplitude?
balandron [24]

Answer:

I think its the Blue wave, im not sure so dont take my word for it.

Explanation:

3 0
3 years ago
Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t
s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1=\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2) because the derivate of the position is the velocity

V1=12t+3

V2=20+\int\limits^_ {} \,-8t because the integral of the acceleration is the velocity

V2=20-4t^{2}

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with \frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0
3 years ago
Most grandfather clocks have pendulums with adjustable lengths. One such clock gains 10 min per day when the length of its pendu
7nadin3 [17]

The length to which the pendulum will be adjusted to keep perfect time is 29.59 inches. See the explanation below.

<h3>What is the justification for the above answer?</h3>

T1 = 2πR√(L1/GM)

and

T2 = 2πR√(L1/GM)

T1/T2 = √(L1/L2).

If the pendulum has an efficient period, that means it executes with perfect frequency.

Thus,

T2 = (24 * 60)/x

= 1440/x

This means that in one day, there are perfect cycles of represented by "x". Note that there are 1440 minutes in one day.

If the other Pendulum is slower by 10 minutes, that means

T1 = 1450/x

Hence

(1450/x)/(1440/x) = √(L1/L2).

⇒ 1450/1440 = √(L1/L2).

Thus,

(1450/1440)² = 30/L

L = 30/(1450/1440)²

L = 30/(1.00694444444)²

L = 30/1.01393711419

L = 29.5876337695

L $\approx$ 29.59 inches.

Hence, the pendulum will need to be adjusted by 29.59 inches to ensure that the clock keeps perfect time.

Learn more about pendulum problems:

brainly.com/question/16617199

#SPJ4

3 0
2 years ago
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