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Vinil7 [7]
4 years ago
15

Potential Difference Across Axon Membrane The axoplasm of an axon has a resistance Rax. The axon's membrane has both a resistanc

e (Rmem) and a capacitance (Cmem). A single segment of an axon can be modeled by a circuit with Rmem and Cmem in parallel with each other and in series with an open switch, a battery, and Rax. Imagine the voltage of the battery is ΔV. Part A We can model the firing of an action potential by the closing of the switch, which completes the circuit. Immediately after the switch closes, what is the potential difference across the membrane of this single segment?

Physics
1 answer:
Korolek [52]4 years ago
6 0

Answer:

<em>check the diagram in the attachment below.</em>

After the switch closes, the voltage across the membrane will be zero. It is so due to the fact that the  capacitor will be short circuited.

Explanation:

question

Potential Difference Across Axon Membrane The axoplasm of an axon has a resistance Rax. The axon's membrane has both a resistance (Rmem) and a capacitance (Cmem). A single segment of an axon can be modeled by a circuit with Rmem and Cmem in parallel with each other and in series with an open switch, a battery, and Rax. Imagine the voltage of the battery is ΔV. Part A We can model the firing of an action potential by the closing of the switch, which completes the circuit. Immediately after the switch closes, what is the potential difference across the membrane of this single segment?

ANSWER;

After the switch closes, the voltage across the membrane will be zero. It is so due to the fact that the  capacitor will be short circuited.

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Answer

given,

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mass of car A = m_a = 1300 kg

velocity of car A = v_a  = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b  = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

P_1 = m_av_a + m_b v_b

P_1 = 1300 \times 35+ 1000 \times 25

P_1 =70500 Kg.m/s

final momentum

P_2 = m_aV_a + m_b V_b

P_2 = 1300 \times 30+ 1000 \times 31.5

P_2 =70500 Kg.m/s

here  initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

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What is the modern<br> Jatomic theory?
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<u>Answer:</u>

The modern atomic theory has given by "John Dalton and framed postulates".

<u>Explanation:</u>

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You stand on a bridge above a river and drop a rock into the water below from a height of 25 m. (Assume no air resistance)
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PART a)

here when stone is dropped there is only gravitational force on it

so its acceleration is only due to gravity

so we will have

a = g = 9.8 m/s^2

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y = v_i t + \frac{1}{2} at^2

now we have

y = 25 m

so from above equation

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If we throw the rock horizontally by speed 20 m/s

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