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3 years ago

HURRY!!!!!!!

2 answers:

7 0

The basic relationship between capacitance (C), charge (Q) and voltage (V) for a parallel-plate capacitor is
$C= \frac{Q}{V}$
in our problem, $C=0.40 \mu F=0.40 \cdot 10^{-6} F$ and V=9.0 V, so the charge on each plate is
$Q=CV=(0.40 \cdot 10^{-6}F)(9.0 V)=3.6 \cdot 10^{-6} C$

zzz [600]3 years ago

5 0

Answer:

3.6

Explanation:

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A wind-tunnel experimentis performed on a 1/25scale model of a supersonic aircraft. The prototype aircraft flies at 450 m/s in c

KengaRu [80]

Answer: V = 504m/a

F = 4N

Explanation: please find the attached file for the solution

4 0

3 years ago

The standard wave format for any wave is

Novay_Z [31]

The standard wave format for any wave is transverse wave

8 0

3 years ago

A thin film of cryolite ( nc = 1.34 ) is applied to a camera lens ( ng = 1.58 ). The coating is designed to reflect wavelengths

rosijanka [135]

Answer:

=99.07nm

Explanation:

minimum thickness

2nd = (m - 1/2)λ

d = (m - 1/2)(λ/2n)

refractive index of the thin film, n = 1.34

minimum thickness m = 1

light wavelength λ = 531nm

d = (1 - 1/2) (531 / (2)(1.34)

d = 531/5.36

= 99.07nm

3 0

3 years ago

The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s

Bumek [7]

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: $m_{(t)} =m_{0} e^{-kt}$ , where $m_{0}$ is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

$m_{(1)} =m_{0} e^{-k(1)}$ , but $m_{(1)}=\frac{99m_{0} }{100}$ , so we have $\frac{99m_{0} }{100}=m_{0}e^{-k}$ , then $k=-ln(\frac{99}{100})=0.01$

Now using k found we must to find $m_{(5)}$ .

$m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg$

6 0

3 years ago

State and explain guass law?

julia-pushkina [17]

"Gauss's Law. The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. ," Source: <span>hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html

If you would like more info please look at the website. Im only in middle school, so I am sorry if this is not what you were looking for.....</span>

3 0

3 years ago