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2 answers:
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Answer:
B = 0.37T
Explanation:
In order to calculate the needed magnitude of the magnetic force you use the following formula, which calculate the induced emf of the solenoid when there is a change in the magnetic flux:
(1)
emf: induced voltage in the solenoid = 10,000V
N: turns of the solenoid = 525
ФB: magnetic flux
B: magnitude of the magnetic field = ?
A: cross-sectional area of the solenoid = π*r^2
r: radius of the cross-sectional area = 0.260m
Δt: interval time of the change of the magnetic flux = 4.17ms = 4.17*10^-3s
First, you have the magnetic field direction perpendicular to the plane of the solenoid, after, the angle between them is 90° (quarter of a revolution)
In the equation (1) the only parameter that changes on time is the angle, then, you can solve for B from the equation (1):
Finally, you replace the values of the parameters to calculate B:
The strength of the magnetic field is 0.37T
Answer:
T₂ = 2482.34 N
Explanation:
Equations of balance of forces
Look at the force diagram in the attached graph:
∑Fx=0
T₂cos α -T₁senα = 0 Equation (1)
∑Fy=0
T₁cos α +T₂sinα-W =0 Equation(2)
Data
m=539 kg
g= 9.8 m/s²
W= m*g= 539 kg* 9.8 m/s²= 5282.2 N
T₁ = 1.88T₂
Problem development
in the equation (1)
T₂cos α-(1.88T₂)senα = 0 We divided the equation by ( T₂cos α)
1 - (1.88)tanα = 0
tanα= 1/(1.88)
tanα= 0.5319
α = 28°
T₂=(1.88T₂)tanα
in the equation (2)
(1.88T₂)cos α+ T₂sinα - 5282.2 =0 We divided the equation by cos α
1.88T₂+ T₂tanα - 5282.2/cos α =0
1.88T₂+ T₂tan(28°) - 5282.2/(cos 28°) =0
1.88T₂+ (0.53)T₂- 5982.46 =0
(2.41)T₂ = 5982.46
T₂ = 5982.46/(2.41)
T₂ = 2482.34 N
