Answer:
<em>18808.7 m/s^2</em>
Explanation:
Given
Length of the pendulum L = 1.44 m
Number of complete cycles of oscillation n = 1.10 x 10^2
total time of oscillation t = 2.00 x 10^2 s
The period of the T = n/t
T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s
The period of a pendulum is gotten as
T = 
where g is the acceleration due to gravity
substituting values, we have
0.55 = 
0.0875 = 
squaring both sides of the equation, we have
7.656 x 10^-3 = 144/g
g = 144/(7.656 x 10^-3) = <em>18808.7 m/s^2</em>
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
+ 
= 
- 
= 3 kg, = 8 m/s, = 2 kg, = 0 m/s ( since it is at rest), = 2 m/s, = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x )
24 + 0 = 16 - 2
2 = 16 - 24
2 = -8
= 
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
Answer:
that it is bumpy or by the sun
Explanation:
Because a variable is an important stratagy of science
