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4 years ago

During which phase of the moon may a solar eclipse occur?

Physics

2 answers:

alex41 [277]4 years ago

4 0

Answer:

New moon

Explanation:

A solar eclipse can only take place at the phase of new moon, when the moon passes directly between the sun and Earth and its shadows fall upon Earth's surface.

Anna007 [38]4 years ago

4 0

A solar eclipse happens when the moon is perfectly aligned between the Earth and the Sun, thus obscuring it.

If the moon is between the Earth and the Sun, the far side of the moon is lighted, and thus you have a new moon.

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An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same directi

Arturiano [62]

The kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

To find the answer, we have to know about the Lorentz transformation.

<h3>What is its kinetic energy as measured in the Earth reference frame?</h3>

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the kinetic energy as measured in the Earth reference frame, if the landing craft has a mass of 4.00 × 10⁵ kg.

$V_x'=0.8c\\V=0.6c\\m=4*10^5kg$

Let us consider the earth as S frame and space craft as S' frame, then the expression for KE will be,

$KE=m_0c^2=\frac{mc^2}{1-(\frac{v_x^2}{c^2} )}$

So, to $V_x=(0.8+0.6)c-[\frac{0.6c*(0.8c)^2}{c^2}]=1.016$ find the KE, we have to find the value of speed of the approaching landing craft with respect to the earth frame.
We have an expression from Lorents transformation for relativistic law of addition of velocities as,

$V_x'=\frac{V_x-V}{1-\frac{VV_x}{c^2} } \\thus,\\V_x=V_x'(1-\frac{VV_x}{c^2} )+V$

Substituting values, we get,

$V_x=0.8c(1-\frac{0.8c*0.6c}{c^2} )+0.6c=(0.8c*0.52)+0.6c=1.016c$

Thus, the KE will be,

$KE=\frac{4*10^5*(3*10^8)^2}{\sqrt{1-\frac{(1.016c)^2}{c^2} } } =\frac{1.2*10^{22}}{0.179}=6.704*10^{22}J$

Thus, we can conclude that, the kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

Learn more about frame of reference here:

brainly.com/question/20897534

SPJ4

3 0

2 years ago

A carnot engine operates between two heat reservoirs at temperatures th and tc. an inventor proposes to increase the efficiency

Sonja [21]

The efficiency of the first Carnot engine is
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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5 0

3 years ago

A) Calculate the pressure of water at the bottom of a well if the depth

Molodets [167]

Answer: 98000pa

Explanation:Given,

Depth(h)=10m

gravity(g)=9.8m/s

density(δ)=1000kg/m^3

we know,

P=hdg

P=10*1000*9.8

P=98000pa

7 0

3 years ago

If the period of a given wave is 6 seconds what si the frequency of the wave

Veronika [31]

Frequency =1/period
Freq= 1/6= 0.17 Hertz

3 0

3 years ago

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 . The expl? After landing on

iogann1982 [59]

<span>We can find the period P of one cycle, and then we can use the period to find the gravitational acceleration g on this planet. P = (132 s) / (107 cycles) = 1.2336 s/cycle The period P is 1.2336 seconds. This means that it takes 1.2336 seconds for the pendulum to swing back and forth one. Now we can use the period P to find the gravitational acceleration g. The equation for the period of a pendulum is as follows: P = 2 pi \sqrt{L/g} P^2 = (4 pi^2) L / g g = (4 pi^2) L / P^2 g = (4)(pi^2)(0.540 m) / (1.2336 s)^2 g = 14.0 m/s^2 The acceleration of gravity on the planet is 14.0 m/s^2.</span>

7 0

3 years ago