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Burka [1]
3 years ago
12

Buffering capacity refers to: the effectiveness of commercial antacids the extent to which a buffer solution can counteract the

effect of added acid or base the pH of a buffer solution the molecular weight of the substance used as a buffer.
Chemistry
1 answer:
kirill [66]3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

Buffere is defined as the solution to whom when an acid or base is added then it resists any in change in pH of the solution.

This is because a buffer has the ability to not get affected by the addition of small amounts of an acid or a base. So, basically it keeps the concentration of both hydrogen ions and hydroxides equal. As a result, it helps in maintaining the pH of the solution.

And, the capacity of a buffer solution to resist the change is known as buffer capacity.

Thus, we can conclude that buffering capacity refers to the extent to which a buffer solution can counteract the effect of added acid or base.

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If the crucible wasn't covered with a lid the reactants may have produced a gas that was released into the surroundings, or mass may have been lost in the form of water vapour.
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3 years ago
What is the ph of a 3x10-8M H+ solution
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Answer:

The pH of the solution is 7, 52

Explanation:

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4 0
3 years ago
Calculate the pH of a solution in which one normal adult dose of aspirin (640 mg ) is dissolved in 10 ounces of water. Express y
d1i1m1o1n [39]

The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Given data :

mass of aspirin = 640 mg = 0.640 g

volume of water = 10 ounces = 0.295735 L

molar mass of aspirin = 180.16 g/mol

moles of aspirin = mass / molar mass = 0.00355 mol

<h3>Determine the pH of the solution </h3>

First step : <u>calculate the concentration of aspirin</u>

= moles of Aspirin / volume of water

= 0.00355 / 0.295735

= 0.012 M

Given that pKa of Aspirin = 3.5

pKa = -logKa

therefore ; Ka = 10^{-3.5} = 3.162 * 10^{-4}

From the Ice table

3.162 * 10^{-4} = \frac{x + H^+}{[aspirin]}  = \frac{x^{2} }{0.012-x}

given that the value of Ka is small we will ignore -x

x² = 3.162 * 10^{-4} * 0.012

x = 1.948 * 10^{-3}  

Therefore

[ H⁺ ] = 1.948 * 10^{-3}

given that

pH = - Log [ H⁺ ]

     = - ( -3 + log 1.948 )

     = 2.71 ≈ 2.7

Hence we can conclude that The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Learn more about Aspirin : brainly.com/question/2070753

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