What is the energy of a photon with a 6 micrometer wavelength (1 m = 106 micrometers)?

What is a binary acid?

Alona [7]

Answer:

look down yonder

Explanation:

5 0

3 years ago

Predict the sign of the entropy change of the system for each of the following reactions.

storchak [24]

Answer :

(a) The entropy change will also decreases.

(b) The entropy change will also increases.

(c) The entropy change will also decreases.

(d) The entropy change will also increases.

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

(a) $N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

In this reaction, the randomness of reactant molecules are more and as we move towards the formation of product the randomness become less that means the degree of disorderedness decreases. So, the entropy change will also decreases.

(b) $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

In this reaction, the randomness of reactant molecules are less and as we move towards the formation of product the randomness become more that means the degree of disorderedness increase. So, the entropy change will also increases.

(c) $3C_2H_2(g)\rightarrow C_6H_6(g)$

In this reaction, 3 mole of gaseous $C_2H_2$ react to give 1 mole of gaseous $C_6H_6$ that means randomness become less that means the degree of disorderedness decreases. So, the entropy change will also decreases.

(d) $Al_2O_3(s)+3H_2(g)\rightarrow 2Al(s)+3H_2O(g)$

In this reaction, the number of moles of gases are same on both side of the reaction but 1 mole of solid $Al_2O_3$ react to give 2 moles of solid aluminium that means randomness become more that means the degree of disorderedness increases. So, the entropy change will also increases.

5 0

3 years ago

Given the following reaction: 3CuCl2(aq) 2Na3PO4(aq) --> Cu3(PO4)2(s) 6NaCl(aq) MM (g/mol) 134.45 163.94 380.58 58.44 If 285

nata0808 [166]

Answer:

227.78g of the precipitate are produced

Explanation:

Based on the reaction, 3 moles of CuCl2 produce 1 mole of Cu3(PO4)2 (The precipitate).

To solve this question we need to find the moles of CuCl2 added. With these moles and the reactio we can find the moles of Cu3(PO4)2 and its mass as follows:

Moles CuCl2:

285mL = 0.285L * (6.3mol / L) = 1.7955 moles CuCl2

Moles Cu3(PO4)2:

1.7955 moles CuCl2 * (1mol Cu3(PO4)2 / 3mol CuCl2) = 0.5985 moles Cu3(PO4)2

Mass Cu3(PO4)2 -380.58g/mol-

0.5985 moles Cu3(PO4)2 * (380.58g/mol) =

227.78g of the precipitate are produced

7 0

3 years ago

Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr

pantera1 [17]

Answer:

$m_{CuO}=93.6gCuO$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2$

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

$m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO$

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

$m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO$

Regards.

6 0

3 years ago

Into what kinds of energy does a toaster convert electrical energy?

KengaRu [80]

the answer is C. light and heat

6 0

3 years ago

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