Answer:
1/3 you will add it to get your main description and get your final answer
Answer:
The answer is to the question is 13
<span>The equation would be 5x + 0.10y = 35, and since y equals 100, the 0.10y = 10. Then you get your equation which would be 5x + 10 = 35. and you can use subtraction property of equality and subtract 10 from both sides which gives you 25. So x would equal 5. In this case x represents number of dogs walked. Hope this helps! :D</span>
Domain- {-2, 1, 0, 1, 2}
Range- {-2, 0, 2}
My domain is right but I don’t think my range is. I did learn this 4 years ago though so
Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.
<h3>What is Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is
, therefore, in order to find the value of f(5), we need to calculate the value of f(4).
f(2)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%282%29%3Df%281%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%281%29%5D%5C%5C%5C%5Cf%282%29%20%3D%202.5%20%5Ctimes%203.2%5C%5C%5C%5Cf%282%29%20%3D%208)
f(3)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%283%29%3Df%282%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%282%29%5D%5C%5C%5C%5Cf%283%29%20%3D%202.5%20%5Ctimes%208%5C%5C%5C%5Cf%283%29%20%3D%2020)
f(4)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%284%29%3Df%283%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%283%29%5D%5C%5C%5C%5Cf%284%29%20%3D%202.5%20%5Ctimes%2020%5C%5C%5C%5Cf%284%29%20%3D%2050)
f(5)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%285%29%3Df%284%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%284%29%5D%5C%5C%5C%5Cf%285%29%20%3D%202.5%20%5Ctimes%2050%5C%5C%5C%5Cf%285%29%20%3D%20125)
Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.
Learn more about Function:
brainly.com/question/5245372