What are the 4 variables that describe a gas

1. Which type of compound usually has higher melting points: ionic compounds or covalent compounds? What is the reason for this

ELEN [110]

Ionic compounds have stronger bonds so a lot of energy is needed to break the bonds.

3 0

2 years ago

1. the smallest complete unit of a compound or diatomic gas shell

kogti [31]

Answer:

Explanation:

1. The smallest complete unit of a compound or diatomic gas

ATOM

Atoms are small tiny particles that makes up a molecule. It is regarded as the smallest indivisible particle that parts in a chemical reaction.

2. A new substance formed by the combination of two or more different atoms

COMPOUNDS

Compounds are substances composed of two or more kinds of atoms. Their properties differs from those of the constituent elements that combines to make them up.

3. Path of electrons around an atomic nucleus

SHELL

The shell describes the path of an electron round a nucleus

4. A substance consisting of only one type of atom

MONOATOMIC MOLECULE

It is an aggregate of one type of atom.

5 0

3 years ago

What is the difference between dissolving and dissociating and how does this relate to the van't hoff factor?

Nastasia [14]

Solvation is the process of dissolving.

Dissociation is the separation of a substance into charged components during dissolution.

<h3>What is the difference between dissolving and dissociating?</h3>

Dissolution (dissolving), which simply refers to becoming solvated by the solvent, is a subset of dissociation, which is particularly the separation of two charged ions in solution. When the solvent completely envelops each individual solute molecule, solvation takes place. By definition, something that is dissociated in a solvent must be dissolved in it. For instance, the salt dissociates in water, which is how it dissolves in water. In water, ethanol dissolves but does not dissociate; it remains ethanol.

<h3>How does Van't Hoff's factor work?</h3>

The Van't Hoff factor is a tool used to compare the real number of moles of solute injected to create a solution to the apparent amount produced by colloidal characteristics.

<h3>What is the Van't Hoff factor's value?</h3>

Van't Hoff factor's value is:-

No association or dissociation i=1
Dissociation i<1
Association i>1

Learn more about Van't Hoff's factor here:-

brainly.com/question/24598605

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6 0

1 year ago

Which of the following objects would float when placed in water? (Note: 1 mL 1 cm+3)*

liraira [26]

Only an apple will float when placed in water.

An object will float in water if its density is <em>less than that of water</em> (1.0 g/mL).

An object will sink in water if its density is <em>greater than that of water</em>.

Thus, solid objects made of <em>gold, iron, or rubber</em> will all sink in water.

6 0

3 years ago

Your job is to determine the concentration of ammonia in a commercial window cleaner. In the titration of a 25.0 mL sample of th

ruslelena [56]

Answer:

The initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of HCl solution = 0.164 M

Volume of solution = 23.8 mL = 0.0238 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.164M=\frac{\text{Moles of HCl}}{0.0238L}\\\\\text{Moles of HCl}=(0.146mol/L\times 0.0238L)=0.0035mol$

The chemical equation for the reaction of ammonia and HCl follows:

$NH_3+HCl\rightarrow NH_4^++Cl^-$

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of ammonia

So, 0.0035 moles of HCl will react with = $\frac{1}{1}\times 0.0035=0.0035mol$ of ammonia

Calculating the initial concentration of ammonia by using equation 1:

Moles of ammonia = 0.0035 moles

Volume of solution = 25 mL = 0.025 L

Putting values in equation 1, we get:

$\text{Initial concentration of ammonia}=\frac{0.0035mol}{0.025L}=0.14M$

By Stoichiometry of the reaction:

1 mole of ammonia produces 1 mole of ammonium ion

So, 0.0035 moles of ammonia will react with = $\frac{1}{1}\times 0.0035=0.0035mol$ of ammonium ion

Calculating the concentration of ammonium ion by using equation 1:

Moles of ammonium ion = 0.0035 moles

Volume of solution = [23.8 + 25] mL = 48.8 mL = 0.0488 L

Putting values in equation 1, we get:

$\text{Molarity of ammonium ion}=\frac{0.0035mol}{0.0488L}=0.072M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.8\times 10^{-5}$

$10^{-14}=1.8\times 10^{-5}\times K_a\\\\K_a=\frac{10^{-14}}{1.8\times 10^{-5}}=5.55\times 10^{-10}$

The chemical equation for the dissociation of ammonium ion follows:

$NH_4^+\rightarrow NH_3+H^+$

The expression of $K_a$ for above equation follows:

$K_a=\frac{[NH_3][H^+]}{[NH_4^+]}$

We know that:

$[NH_3]=[H^+]=x$

$[NH_4^+]=0.072M$

Putting values in above expression, we get:

$5.55\times 10^{-10}=\frac{x\times x}{0.072}\\\\x=6.32\times 10^{-6}M$

To calculate the pH concentration, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=6.32\times 10^{--6}M$

$pH=-\log (6.32\times 10^{-6})\\\\pH=5.20$

Hence, the initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

5 0

2 years ago