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aleksley [76]
3 years ago
12

5. Tree sap can be a very concentrated solution of solutes in water. These are mostly sugars, with van’t Hoff factors of 1. The

root system provides a semi-permeable membrane across which water moves to “dilute” the sap, providing a significant osmotic pressure.
a. If a tree sap has an effective concentration of 37 Molar, what pressure is generate at 298K across the endodermis root membrane? R = 0.08216 L.atm/mol.K.

b. If an osmotic pressure of 1.0 atm can raise a volume of water 10.33 meters high, how high can the sap of this tree rise?
Chemistry
1 answer:
murzikaleks [220]3 years ago
5 0

Answer:

a)905,89 atm of pressure will be generated at 298K.

b)The sap of tree can rise upto 9,357.84 meters.

Explanation:

a)

Effective concentration of sap = c = 37 M

Osmotic pressure generate at 298K = \pi

Temperature ,T = 298 K

\pi =cRT

\pi =37 mol/L\times 0.08216 atm L/mol L\times 298 K

\pi =905.89 atm

905,89 atm of pressure will be generated at 298K across the endodermis root membrane.

b)

Given that 1.0 at of pressure raises the volume of water upto height of 10.33 m

Then 905.89 atm of pressure will raise the height of water upto:

\frac{10.33}{1.0}\times 905.89 m=9,357.84 m

The sap of the tree can rise upto 9,357.84 meter.

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Life on Earth is based on carbon, likely because each carbon atom can form bonds with up to four other atoms simultaneously. This quality makes carbon well-suited to form the long chains of molecules that serve as the basis for life as we know it, such as proteins and DNA.

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3 years ago
What is the name of the binary molecule H2O2? This compound is also known as hydrogen peroxide and is a properly disinfectant or
Masteriza [31]

Answer:

hydrogen dioxide

Explanation:

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4 years ago
T OR F
Murljashka [212]

Answer:

The statement is  false. See the explanation below, please.

Explanation:

The hydrogen bond or bridge is a type of dipole-dipole interaction that is generated from the attraction of a hydrogen atom and a very electronegative atom (oxygen, fluorine or nitrogen). Examples of hydrogen bridge molecules: Water (H20), ammonia (NH3).

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A formic acid buffer solution contains 0. 20 m h c o o h hcooh and 0. 24 m h c o o − hcoox−. the pka of formic acid is 3. 75. wh
irina1246 [14]

A buffer solution contains an equivalent amount of acid and base. The pH of the solution with an acid dissociation constant (pKa) value of 3.75 is 3.82.

<h3>What is pH?</h3>

The amount of hydrogen or the proton ion in the solution is expressed by the pH. It is given by the sum of pKa and the log of the concentration of acid and bases.

Given,

Concentration of salt [HCOO⁻] = 0.24 M

Concentration of acid [HCOOH] = 0.20 M

The acid dissociation constant (pKa) = 3.75

pH is calculated from the Hendersons equation as,

pH = pKa + log [salt] ÷ [acid]

pH = 3.75 + log [0.24] ÷ [0.20]

= 3.75 + log (1.2)

= 3.75 + 0.079

= 3.82

Therefore, 3.82 is the pH of the buffer.

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6 0
2 years ago
The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g
ra1l [238]

Answer:

1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

6.97g.\frac{1mol}{22.98g} .\frac{-369kJ}{2mol} =-56.0kJ

2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g)  ΔH = 2.80 kJ

The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:

10.4g.\frac{1mol}{28.01g} .\frac{2.80kJ}{mol} =1.04kJ

3 0
4 years ago
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