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Alik [6]
3 years ago
7

Draw two cyclic constitutional isomers of cis-1-chloro-2-methylcyclobutane with the same size ring. In cases where there is only

one cyclic constitutional isomer, just draw one structure.

Chemistry
1 answer:
igomit [66]3 years ago
3 0

Answer:

The drawings are in the figure attached below.

Explanation:

"Constitutional isomers" is a term used in chemistry to refer to chemical compounds that have the same constitution and molecular formula distributed in a different structure. That is, the compound has the same atoms, but when built in a three-dimensional image, these atoms occupy different places within the same structure.

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What is the H+ concentration for an aqueous solution with pOH = 4.01 at 25 ∘C? Express your answer to two significant figures an
EleoNora [17]

I believe pH = -log[H+]

Also, 14 = pH + pOH

Therefore pH = 14 - pOH

pH = 14 - 4.01

pH = 9.99

9.99 = -log[H+]

Solve for H+

5 0
3 years ago
If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?
NARA [144]
I have attached a photo of the structure. 
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5 0
3 years ago
What is the scientific term for rocks made in lava?
Elden [556K]

The answer is d. extrusive.


The other term for it is <em>igneous rock</em>. Igneous rock is made in lava, and another term for igneous rock is extrusive rock.


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5 0
3 years ago
Read 2 more answers
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai
Rama09 [41]

We are given –

  • Final velocity of car is, v= 0
  • Initial velocity of car is, u= 100 km/hr
  • Time taken, t is = 3 minutes or 180 sec

Here–

\qquad\pink{\bf \longrightarrow  Initial\:  velocity =  100 \:km/hr}

\qquad\sf \longrightarrow  Initial\:  velocity = \dfrac{ 100 \times 1000}{3600} \:m/s

\qquad\pink{ \bf \longrightarrow  Initial\:  velocity = 27.78\: m/s}

Now –

\qquad____________________________

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{Final\: Velocity -Initial  \:Velocity }{Time}}

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{v -u}{t}}

\qquad\sf \longrightarrow  Acceleration = \dfrac{(0- 27.78)}{1800}

\qquad\sf \longrightarrow  Acceleration =\cancel{ \dfrac{- 27.78}{1800}}

\qquad\purple{\bf \longrightarrow  Acceleration = -0.15 \: m/s^2}

\qquad_______________________________

6 0
2 years ago
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