The way I figured this one out was saying that if it takes 2lbs to stretch it to 12 inches and 5lbs to stretch to 18 inches that means that 3 additional pounds = 6 inches. Therefore, each additional pound is 2 inches. We know already that with 2 lbs it was 12 inches in length and we can also say that 2 lbs = 4 inches. So subtract 4 from 12 and you end up with the answer of 8 inches.
Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>
Answer: 24y - 8w + 16
Step-by-step explanation:
Basically to remove the parenthesis you just distribute the -4 outside of the parenthesi and you get 24y - 8w + 16.
Answer:
14,28,42 and 56
Step-by-step explanation:
Multiply all lengths by 2 as the quadrilateral is dilated by a scale factor of 2
Answer:
3^2/15
Step-by-step explanation:
(^5sqrt3^2)^1/3
(3^2/5)^1/3
multiply the powers
3^2/5*1/3
3^2/15