<span>Galvanized steel is preferred for outdoor uses because it is ideal to prevent rotting/corrosion
A steel will rot more quickly if it's exposed to a larger amount of oxygen and H2O , which will exist if we put it oudoor
Coating the steel with additional zinc will slow down the process</span>
Some parts of a plant can be white because they do not contain chlorophyll.
Chlorophyll is a term to refer to a characteristic compound of most plants that has the function of:
- Bring the green color to vegetables
- Take charge of the photosynthesis process.
Some plants do not have as much chlorophyll in their systems. However, this does not affect their reproduction and growth because they have developed other feeding methods through their roots.
These plants that contain low amounts of chlorophyll have pale and white colorations because chlorophyll is what gives the plants their intense green color.
Note: This question is incomplete because options are missing. Nevertheless, I can answer it based on my prior knowledge.
Learn more in: brainly.com/question/14884020
Answer:
The answer is below
Explanation:
Sulfuric acid is used for various purposes, some of which include the following:
1. It is used in the production of various manufactured goods.
2. It is used in the manufacturing of chemicals
3. It is also used in the making of fertilizer
4. It is used in the refining process of petroleum products
5. It is used in the processing of metals
Answer:
Explanation:
From the information given:
no of moles of 
= 0.01 L × 0.0010 mol/L
no of moles of = 
no of moles of 
= 0.01 L × 0.00010 mol/L
no of moles of = 
Total volume = 0.02 L
![[Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%7D%5D%20%3D%20%5Cdfrac%7B1%5Ctimes10%5E%7B-5%7D%20%5C%20mol%7D%7B0.02%20%5C%20L%7D%20%5C%5C%20%5C%5C%20%20%5C%5C%20%20%5C%5B%5BCa%5E%7B2%2B%7D%7D%5D%20%3D%200.0005%20%5C%20mol%2FL)
![[F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%20%3D%20%5Cdfrac%7B%281%5Ctimes%2010%5E%7B-6%7D%20%5C%20mol%29%7D%7B0.02%20%5C%20L%7D)
![[F^{-}] = 5 \times 10^{-5} \ mol/L](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%20%3D%205%20%5Ctimes%2010%5E%7B-5%7D%20%20%5C%20mol%2FL)
![Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}](https://tex.z-dn.net/?f=Q%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2%20%5C%5C%20%5C%5C%20Q%20%3D%200.0005%20%5Ctimes%20%285%5Ctimes%2010%5E%7B-5%7D%29%5E2%20%5C%5C%20%5C%5C%20Q%20%3D%201.25%20%5Ctimes%2010%5E%7B-12%7D)
Since Q<ksp, then there will no be any precipitation of CaF2
Answer:
14915960J
Explanation:
brendatferreira answered it on another slide this person said they used a converter
