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Korvikt [17]
3 years ago
13

What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1120 kilohertz?

Physics
1 answer:
Alex73 [517]3 years ago
6 0

The wavelength of the radio photon  is 268 m.

Electromagnetic waves travel with the speed of 3×10⁸m/s in vacuum. The speed of a wave <em>c i</em>s related to its frequency<em> f</em> and wavelengthλ as follows:

c=f\lambda

Thus the wavelength is given by,

\lambda =\frac{c}{f}

Substitute 3×10⁸m/s for <em>c</em> and 1120×10³Hz for <em>f</em>.

\lambda =\frac{c}{f}\\ =\frac{3*10^8m/s}{1120*10^3Hz} \\ =267.8 m\\ =268 m

Thus the wavelength of the radio photon from an AM station is 268 m

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A bathtub contains 65 gallons of water and the total weight of the tub and water is approximately 931.925 pounds. You pull the p
levacccp [35]

Answer:

Q = 8,345 * v

Explanation:

So, we are looking for an expression of the amount of water that has been drained from the tub. The expression is in terms of v that represent the number of gallons of water drained since the plug was pulled. Since we are interested in the pounds of water that has been drained from the tub we need to take into account that for every gallon of water drained, 8.345 pounds have left the tub. Therefore, the expression for the weight of water Q that has been drained from the tub in terms of v is simply :

Q = 8,345 * v

Where v is the amount of gallons that has been drained from the tub.

Have a nice day. let me know if I can help with anything else

8 0
3 years ago
Bumper of a stationary bumper car. The momentum of the stationary car increases. Which happens to the momentum of the moving bum
Afina-wow [57]

Bumper of a stationary bumper car. The momentum of the stationary car increases. Which happens to the momentum of the moving bumper car? It decreases. It stays the same. It is converted to inertia.

Bumper of a stationary bumper car. The momentum of the stationary car increases. The momentum of the moving bumper car It is converted to inertia.

6 0
3 years ago
Two cellists, one seated directly behind the other in an orchestra, play the same 220-Hz note for the conductor who is directly
Llana [10]

Answer:

d= 1.56 m

Explanation:

In order to have a constructive interference, the path difference between the sources of the sound, must be equal to an even multiple of the semi-wavelength, as follows:

⇒ d = d₂ - d₁ = 2n*(λ/2)

The minimum possible value for this distance, is when n=1, as it can be seen here:

dmin = λ

In any wave, there exists a fixed relationship between the wave speed, the frequency and the wavelength:

v = λ*f

If v = vsound = 343 m/s, and f = 220 1/s, we can solve for λ:

λ =\frac{v}{f} =  \frac{343 m/s}{220(1/s)} = 1.56 m

⇒ dmin =λ = 1.56 m

3 0
3 years ago
A person using an oxygen mask is breathing air that is 33% oxygen. what is the partial pressure of the o2, when the air pressure
yawa3891 [41]
The partial pressure of the O2 is 36.3 kiloPascal when the air pressure in the mask is 110 kiloPascal based on the isotherm relation. This problem can be solved by using the isotherm relation equation which stated as Vx/Vtot = px/ptot, where V represents volume, p represents the pressure, x represents the partial gas, and tot represents the total gas<span>. Calculation: 33/100 = px/110 --> px = 36.3</span>
5 0
3 years ago
A
malfutka [58]

Answer:

<em>The penny will hit the ground at 6.39 seconds</em>

Explanation:

<u>Free Fall</u>

The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:

\displaystyle y=\frac{gt^2}{2}

Where g=9.8\ m/s^2, and t is the time.

Solving for t:

\displaystyle t=\sqrt{\frac{2y}{g}}

Using the value y=200:

\displaystyle t=\sqrt{\frac{2*200}{9.8}}

t=6.39 sec

The penny will hit the ground at 6.39 seconds

4 0
3 years ago
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