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3 years ago

What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1120 kilohertz?

Physics

1 answer:

Alex73 [517]3 years ago

6 0

The wavelength of the radio photon is 268 m.

Electromagnetic waves travel with the speed of 3×10⁸m/s in vacuum. The speed of a wave c is related to its frequency f and wavelengthλ as follows:

$c=f\lambda$

Thus the wavelength is given by,

$\lambda =\frac{c}{f}$

Substitute 3×10⁸m/s for c and 1120×10³Hz for f.

$\lambda =\frac{c}{f}\\ =\frac{3*10^8m/s}{1120*10^3Hz} \\ =267.8 m\\ =268 m$

Thus the wavelength of the radio photon from an AM station is 268 m

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Why isnt this technology used in coal plants

n200080 [17]

Can cause atmospheric problems.

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3 years ago

A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that i

aniked [119]

Answer:

6.384 m/ $sec^{2}$

Explanation:

The velocity is given by;

We know;

PE= mgh

KE= 1/2 m $V^{2}$

but KE=PE

==> 1/2 m $V^{2}$ =mgh

==> 1/2 $V^{2}$ =gh

==> $v=\sqrt{2gh}$

puting g=9.8 m/sec2

h=2.08 m

==> $v= 6.384 m/sec^{2}$ =

8 0

2 years ago

The flow of air caused by blend in the blank creates distant blank on earth surface

Mamont248 [21]

Question:

The flow of air caused by _____ and the Coriolis effect creates distinct _____ on Earth's surface.

Answer:

Differences in heating
Wind patterns

Explanation:

The flow of air caused by variations in the rate at which the different parts are heated up as well as the Coriolis effect combine to create distinct wind patterns on Earth's surface.

The Coriolis Effect is used to describe a "force" that causes things (like objects, planes, air currents) traveling long distances around the Earth to appear to bend as they move rather than in a straight line.

Cheers

8 0

2 years ago

An oscillator consists of a block attached to a spring (k = 500 N/m). At some time t, the position (measured from the system's e

Alex_Xolod [135]

Answer:

a) $\omega = 10.407\,\frac{rad}{s}$ , b) $m = 4.617\,kg$ , c) $A = 1.355\,m$

Explanation:

a) The system have a simple armonic motion, whose position function is:

$x(t) = A\cdot \cos (\omega\cdot t + \phi)$

The velocity function is determined by deriving the position function in terms of time:

$v(t) = -\omega \cdot A \cdot \sin(\omega\cdot t + \phi)$

The acceleration function is found by deriving again:

$a(t) = -\omega^{2} \cdot A \cdot \cos (\omega\cdot t + \phi)$

Let assume that $t = 0\,s$ . The following nonlinear system is built:

$A\cdot \cos \phi = 0.660\,m$

$-\omega \cdot A \cdot \sin \phi = -12.3\,\frac{m}{s}$

$-\omega^{2}\cdot A \cdot \sin \phi = -128\,\frac{m}{s^{2}}$

System can be reduced by divinding the second and third expressions by the first expression:

$\omega \cdot \tan \phi = 18.636\,\frac{1}{s}$

$\omega^{2}\cdot \tan \phi = 193.94\,\frac{1}{s^{2}}$

Now, the last expression is divided by the first one:

$\omega = 10.407\,\frac{rad}{s}$

b) The mass of the block is:

$m = \frac{k}{\omega^{2}}$

$m = \frac{500\,\frac{N}{m} }{(10.407\,\frac{rad}{s})^{2} }$

$m = 4.617\,kg$

c) The phase angle is:

$\phi = \tan^{-1} \left(\frac{18.636\,\frac{1}{s} }{\omega} \right)$

$\phi \approx 0.338\pi$

The amplitude is:

$A = \frac{0.660\,m}{\cos 0.338\pi}$

$A = 1.355\,m$

8 0

3 years ago

Read 2 more answers

To calculate lobe lift, you need to know the _______ diameter and the lobe height

svetoff [14.1K]

The answer is the diameter of the cam shaft.

This is used to compute for the area of the circle so you can multiply it with the rocker ratio to get maximum amount of weight the valve can lift.

5 0

2 years ago

Read 2 more answers