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svetlana [45]
4 years ago
15

Jasmine makes a note card about series circuits. She records the points shown.

Physics
2 answers:
Alex17521 [72]4 years ago
8 0

Answer:

The correct answer is C.

Explanation:

When we read our example, we can see that we have 4 solutions. And we have table with advantages and disadvantages.

So Jasmine will correct the error on her not card when she is moving point (2) into the Advantages column from Disadvantages column.

vovangra [49]4 years ago
5 0

Answer: C

Explanation:

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Answer:

Explanation:W=F*S

W=work =?

F=force =500N

S=displacement =0m

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What happens when velocity and acceleration are not in the same direction?
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I think it becomes a negative integer?

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The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on
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A particle moves in a straight line so that time t seconds its displacement is x metres from a fixed point is given by x=3t^2 +2
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Answer:

-5 meters

Explanation:

x = 3t² + 2t − 5

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6 0
4 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
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