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ira [324]
4 years ago
9

look around you to find an object in motion .describe the objects motion by discussing its position and direction of motion in r

elation to a refrences point . explain how you could determine the objects speed.
Physics
1 answer:
VARVARA [1.3K]4 years ago
7 0
An example you could use for this would be if you threw a pencil across the room 10m away. the pencil would have travelled 10m(N). you could determine the objects speed by using the formula speed=distance/time. you would have had to time how long it took for the pencil to hit the 10m marking and divide 10 by however many seconds it took.
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A 142 kg boulder is located near the edge of a cliff 25 m above the ground. What is the gravitational potential energy of the bo
jarptica [38.1K]
PE = mass * height * 9.81
PE = 142 * 25 * 9.81
PE = 34825.5 J
8 0
3 years ago
Read 2 more answers
Is gravity constant over the entire earth surface.<br>Explain why?​
masha68 [24]

Gravity is often assumed to be the same everywhere on Earth, but it varies because the planet is not perfectly spherical or uniformly dense. In addition, gravity is weaker at the equator due to centrifugal forces produced by the planet's rotation

5 0
3 years ago
Problem: A lossless 50-Ω transmission line is terminated in a load with ZL = (50 + j25) Ω. Use the Smith chart to find the follo
Nadya [2.5K]

Answer:  (a). ΓL = 0.246 < 75°

(b). S =  1.7

(c). Zin =  (30-j)λ

(d). jreal = Arc Po = 0.105λ

(e). jmax = jreal = 0.105λ

Explanation:

attached is a document to help in understanding.

So we will begin with a step by step analysis of the problem.

from the diagram we have that  ZL = (50 + j25) Ω.

where ZL = ZL / Z₀ = 50 + j25 / 50 = 1 + j0.5

so we mark this on the chart as point 'P'

(a) ΓL = mP/m 'P' < Θ L = 1.7/6.9 < 75°

        ΓL = 0.246 < 75°

(b) This s-circle 's' is given thus s = r = 1.7 on the RHS of the chart

       S =  1.7

(c) we are to calculate the input impedance;

ζin = Q = 0.6 - j0.02

therefore Zin = Z₀ζin = 50(0.6 - j0.02) = (30-j)λ

Zin = (30-j)λ

(d) here we are taking R as the diameter opposite of Q on the s=circle

   so R = γin = 1.7 + j0.02

         yin = yo (γin) = (1.7+j0.02) / 50 = (34 + j0.4)ms

          yin = (34 + j0.4)ms

(e) move from 'p' on s-circle to 'o'

where maximum impedance = Znxl = Zos

which gives jreal =  Arc Po = 0.105λ

(f) jmax = jreal = 0.105λ

cheers i hope this helps

3 0
3 years ago
Which of the following statements is false?
astraxan [27]

Answer:

c. Kinetic energy is conserved in all collisions .

Explanation:

the total kinetic energy of system of particles involved in the collision does changes .

kinetic energy is not conserved in all collisions because in some cases energy is converted to another form of energy that is heat etc .

5 0
4 years ago
How much power is required to do 40 J of work on an object in 5 seconds?
m_a_m_a [10]
C 
because 40 j dived by 5 seconds is 8 work
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3 years ago
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