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3 years ago

A uniform brick of length 18 m is placed

Physics

1 answer:

yuradex [85]3 years ago

3 0

Answer:

13.5

Explanation:

x= Length

.5 = Center Point

x=0.5(9)= 4.5

So total length over the edge will be given as

Length (L) =9+4.5=13.5

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40 POINTS AND RLLY EASY

Fynjy0 [20]

A. Jupiter largest and most massive planet in the solar system

Jupiter has a huge permanent storm that looks like a red spot in images

Jupiter has at least 61 moons orbiting it, some of which are very large

Jupiter located closer to the sun than Kuiper Belt

<h3>Which option that best describes the planet Jupiter?</h3>

Jupiter came on fifth number from the sun and the Jupiter is the massive planet present in our solar system. It contains the big storms like great red spot. The surface of the Jupiter is gas made giant but the surface of the Jupiter is not solid, but it may have a solid inner core about the size of Earth.

The Jupiter contain at least 61 moons which orbiting the Jupiter . The life on the Jupiter is impossible because the Jupiter contain very much pressure, it has volatile surface and the temperature of the Jupiter is very hot than that of the earth.

So we can conclude that option A is the right answer.

Learn more about Jupiter here: brainly.com/question/15044627

#SPJ1

8 0

2 years ago

A vertical spring has a length of 0.25 m when a 0.175 kg mass hangs from it, and a length of 0.775 m when a 2.075 kg mass hangs

Contact [7]

Answer:

A) 35.5N/m b) 20.1cm

Explanation:

Using Hooke's law;

F = Ke where F is the weight of the object = mass of the object in kg * acceleration due to gravity in m/s^2 and k if the force constant of the spring in N/m and e is the extension of the spring which original length of the spring - new length after extension in meters

For the first body, m*g = K * (0.25- li)

Where li is the initial length of the spring

0.175*9.81 = k(0.25-li)

1.72 = k(0.25-li) as equation 1

For the second body, m *g = K* ( 0.775-li)

2.075*9.81 = k (0.775-li) equation 2

20.36 = k(0.775-li)

Make li subject of the formula;

li = 0.775 - 20.36/k

Substitute for li in equation 1

1.72 = k(0.25- (0.775 - 20.36/k))

1.72 = k ( 0.25 - 0.775 + 20.36/k)

Open the bracket with k

1.72 = 0.25k - 0.775k + 20.36 (since k cancel k)

Collect the like terms:

1.72 - 20.36 = - 0.525k

- 18.64 = -0.525k

Divide both side by -0.525

-18.64/-0.525 = -0.525/-0.525k

K = 35.5N/m

B) substitute for k in using

li = 0.775 - 20.36/k

li = 0.775 - 20.36/35.5

li = 0.775 - 0.574

li = 0.201 in meters

li = 0.201 * 100 centimeters = 20.1cm

4 0

3 years ago

What weighs more a mole of feathers or bricks?

harkovskaia [24]

Avogadro's mole is a number, like 6.023 *10^23

your question is the equivalent of asking if 100 feathers or 100 bricks weigh more

the mole of bricks would weigh more

6 0

3 years ago

How do you find the net force acting on an object?

weqwewe [10]

Answer:

C. Add all the force vectors

Explanation:

The net force acting on an object is the vector sum of all the forces on the object.

Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.

For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.

4 0

3 years ago

A single slit 1.4 mmmm wide is illuminated by 460-nmnm light. Part A What is the width of the central maximum (in cmcm ) in the

mamaluj [8]

Answer:

Explanation:

In a single slit experiment, the distance on a screen from the centre point is expressed as y = $\frac{\delta m \lambda d}{a}$ where;

$\delta m$ is the first two diffraction minima = 1

$\lambda$ is light wavelength

d is the distance of diffraction pattern from the screen

a is the width of the slit

Given $\lambda$ = 460-nm = 460*10⁻⁹m

d = 5.0mm = 5*10⁻³m

a = 1.4mm = 1.4*10⁻³m

Substituting this values into the formula above to get width of the central maximum y;

y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³

y = 2300*10⁻¹²/1.4*10⁻³

y = 1642.86*10⁻⁹

y = 1.643*10⁻⁶m

Converting the final value to cm,

since 100cm = 1m

x = 1.643*10⁻⁶m

x = 1.643*10⁻⁶ * 100

x = 1.643*10⁻⁴cm

Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is 1.643*10⁻⁴cm

3 0

3 years ago