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eimsori [14]
3 years ago
12

Hiii please help i’ll give brainliest if you give a correct answer please thanks!

Physics
1 answer:
True [87]3 years ago
5 0

Answer:

The last one " They are equal and act in opposite directions"

Explanation:

Hope u got it right.

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Phương trình trạng thái tổng quát của khí lí tưởng diễn tả là​
tatyana61 [14]

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pV/T=const goodluke

6 0
2 years ago
If you good with science multiple choice
miss Akunina [59]

Answer:

If it had more or less mass, the atmosphere would be very different with either too much ammonia and methane or too little oxygen and water

Explanation:

6 0
2 years ago
An X-ray tube emits X-rays with a wavelength of 1.0 x 10-11 m. Calculate the potential that must be applied across the X-ray tub
sergey [27]

Answer:

1.24 x 10 to the 5 ev = 124,000 ev          its B

Explanation:

E = hc/lambda = 1.24 ev-micrometer/1.0x10 to the -5 micrometers = 1.24 x 10 to the 5 ev = 124,000 ev

h = Planck's constant = 6.626 × 10 to the -34 joule·s

c = speed of light = 2.998 × 10 to the 8 m/s

lambda is the given wavelength

E is the desired photon energy

3 0
3 years ago
Read 2 more answers
What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?
Zepler [3.9K]

Answer:

= 316.67 m/s^2

Explanation:

Acceleration formula =

A = \frac{V_{f}  - V_{i} }{t}

A = \frac{1000 - 50}{3}

= \frac{950}{3}

= 316.67 m/s^2

8 0
2 years ago
Two identical bullets are used. Both are released at the same height - one fired out of a gun, the other is dropped. Ignoring ai
irina [24]

Answer:

Both bullets will hit the ground at the same time.

Explanation:

Let's only analyze the vertical problem.

Any object that is not in the floor or resting in some site is being affected by the gravitational force (remember that we are ignoring air resistance)

Then the acceleration of this object will be equal to the gravitational acceleration:

a = -9.8m/s^2

Where the minus sign is because this acceleration goes down.

To get the velocity equation we need to integrate over time, we will get:

v(t) = ( -9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity.

To get the position equation we need to integrate over time again, we will get:

p(t) = (1/2)*( -9.8m/s^2)*t^2 + v0*t + H

Where H is the initial height.

p(t) = (-4.9 m/s^2)*t^2 + v0*t + H

The object will hit the ground when p(t) = 0

Then we need to solve for t the next equation:

(-4.9 m/s^2)*t^2 + v0*t + H = 0

Notice that the only things we need to know are:

H = initial height (we know that is the same for both bullets)

v0 = initial vertical velocity (also is the same for both bullets)

Notice that the horizontal velocity does not affect this equation, then we will get the same value of t for the dropped bullet and for the fired bullet.

This means that both bullets will hit the ground at the same time.

8 0
2 years ago
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