Ask question

Ask question

All categories

3 years ago

13

Which two statements are true about a system?

2 answers:

Anna11 [10]3 years ago

6 0

<span>The first choice i correct. The second is also correct as it should obey the Law of Conservation of mass. The third choice is incorrect. It depends on the nature of the system. For example, for an ideal gas, you can define at least 2 parameters to set the system boundaries. The fourth choice is incorrect, a system can be theoretical or practical. Hence, the answers are the first and second choices.</span>

mylen [45]3 years ago

3 0

Answer:

1. A system is a group of objects analyzed as one unit.

2. Energy that moves across system boundaries is conserved.

Explanation:

You might be interested in

An isotope of an element will be radioactive if it has an unstable ratio of____and_____

sammy [17]

Neutrons and protons

5 0

4 years ago

Newton's law of gravitation is proportional to the inverse cube of the distance between the two objects.

dimaraw [331]

True hope this helps

7 0

3 years ago

The timing device in an automobile’s intermittent wiper system is based on an RC time constant and utilizes a 0.500 micro F capa

daser333 [38]

Answer:

check 2 photos for answer

check 2 photos for answer

7 0

3 years ago

a coil of wire that is carrying a current and produces a magnetic field is a. a galvanometer. b. a solenoid. c. a magnetic domai

victus00 [196]

It is a solenoid.

The coil of wire looks like a spring and inside of it is a magnetic field

6 0

4 years ago

A ball of mass m = 4.6 kg, at one end of a string of length L= 6.6 m, rotates in a vertical circle just fast enough to prevent t

VashaNatasha [74]

Answer:

v₂ = 17.98 m/s

Explanation:

given,

mass of ball = m = 4.6 Kg

length of string = L = 6.6 m

force acting toward the center is equal to the force exerted by centripetal acceleration

$m g = \dfrac{mv_1^2}{r}$

$v_1 = \sqrt{gr}$

now, calculating the speed of ball at the bottom of the circlr

work done by the gravity = change in kinetic energy

$- m g (2R) = \dfrac{1}{2}m(v_1^2-v_2^2)$

$-4 gR =v_1^2-v_2^2$

$-4 gR =g R-v_2^2$

$v_2^2 = 5 g R$

$v_2=\sqrt{5\times 9.8 \times 6.6}$

v₂ = 17.98 m/s

8 0

3 years ago