Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, in terms of pressures, the rate becomes:
Thus, the rate of change for the partial pressure of ammonia turns out:
![r_{NH_3}=2*(-r_{N_2H_4})\\r_{NH_3}=2*[-(-70torr/h)]\\r_{NH_3}=140torr/h](https://tex.z-dn.net/?f=r_%7BNH_3%7D%3D2%2A%28-r_%7BN_2H_4%7D%29%5C%5Cr_%7BNH_3%7D%3D2%2A%5B-%28-70torr%2Fh%29%5D%5C%5Cr_%7BNH_3%7D%3D140torr%2Fh)
The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.
Best regards.
<span>Calculate the mass of 1 L of solution. Mass of solution=1000mL soln ×1.19 g soln1mL soln =1190 g soln (3 significant figures + 1 guard digit)Calculate the mass of HCl . Mass of HCl=1190g soln ×37.7g HCl100g soln =448.6 g HCl.Calculate the moles of HCl . ...Calculate the molarity of the HCl.</span>
Answer:
the answer is in the picture
The freezing point depression is a colligative property, which means that it depends on the number of particles of solute disolved in the solution.
When you have solutes that are ionic compounds they dissociate in water into ions, then the compound that dissociates more ions will produce more particles and will decrease the freezing point the most.
Given theses aqueous solutions Na2 CO3, Co Cl3, and Li NO3 you can predict the order of the freezing points.
First, write the dissociation equations>
Na2CO3 -> 2Na(+) + CO3 (2-) These are 3 ions: two of Na(+) and one of CO3(2-)
The number inside parenthesis are number of charge not number of molecules.
Co Cl3 -> Co(3+) + 3 Cl (1-) Those are 4 ions: one of Co (+) and three of Cl (-)
Li NO3 -> Li (+) + NO3 (-) those are two ions: one of Li (+) and one of NO3(-)
Then the ionic compound that dissociates into more ions give the solution with lower freezing point, and these is the rank from higher to lower freezing point:
Li NO3 > Na2 CO3 > Co Cl3.
N2 + 3H2 = 2NH3
in this question, we are dealing with only NH3 and H2 so we only focus on that
since the ratio of H2 to 2NH3 is 3:2, we say that
3 liters of H2 = 2 liters of 2NH3
3.6 litres of H2 = x liters of 2NH3
We cross multiple to give:
3 × x = 3.6 × 2
3x = 7.2
Divide both sides by 3
x = 7.2 ÷ 3
x = 2.4liters
