All categories

4 years ago

Which side of the electromagnetic spectrum has shorter wavelengths?

Physics

2 answers:

gtnhenbr [62]4 years ago

8 0

Answer:

Blue, Blue, Blue

Explanation:

I am doing edjunuety right now

Hope this helps

Hatshy [7]4 years ago

8 0

Answer:

Blue , blue , blue

You might be interested in

A projectile is fored vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile.

RSB [31]

Answer:

3683.67 m

Explanation:

Formula for maximum height of projectile is given by the equation;

h = u²/2g

Where u is initial velocity and g is acceleration due to gravity

We are given u = 190 m/s

Thus;

h = 190²/9.8

h = 36100/9.8

h = 3683.67 m

6 0

3 years ago

Một nguồn O phát sóng cơ dao động theo phương trình u = 4cos(4pi t - pi/4). Tốc độ truyền sóng là 1m/s.

brilliants [131]

Answer:

ytrxrddyoxswsdyxgxghfx

jdjdu3jthh

hhhujusbrnog

hhjfjtinrny

ykrjrhrnirjtjjtt

tkrjthr74uu3jt

hri4urjjrjtjjtjtjy

Explanation:

uueuhhhwuejroskanficndui39wn

jebfufkr

5 0

3 years ago

The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid.

kolbaska11 [484]

Answer:

The terminal velocity of the diver is 115 m/s = 414 km/hr

Explanation:

At terminal velocity,

Fnet = mg - Fd = 0

Drag force, Fd = cρAv²/2

mg = cρAv²/2

Terminal Velocity of a body falling through a fluid as in a diver falling through air is given by

v = √(2mg/ρcA)

where m = mass of body falling through fluid = 80 kg

g = acceleration due to gravity = 9.8 m/s²

ρ = density fluid, density of air, as obtained from literature = 1.21 kg/m³

c = coefficient of drag friction of diver falling through air, as obtained from literature = 0.7

A = the area of the diver facing the fluid = 0.14 m²

v = √(2mg/ρcA) = √((2 × 80 × 9.8)/(1.21 × 0.7 × 0.14)) = 115 m/s = 115 × (3600/1000) km/hr = 414 km/hr

5 0

3 years ago

What is a greater force 10 Newtons or 5lbs?

Alexxandr [17]

5lbs is greater.
Hope that helps!

7 0

3 years ago

Read 2 more answers

A current I flows down a wire of radius a.

Helga [31]

Answer:

(a) $K = \frac{I}{2\pi a}$

(b) $J = \frac{I}{2\pi as}$

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

$K = \frac{dI}{dL}$

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

$dL = 2\pi r$

The radius of the wire = a

$dL = 2\pi a$

The surface current density $K = \frac{I}{2\pi a}$

(b) The current density is inversely proportional

$J \alpha s^{-1}$

$J = \frac{k}{s}$ ......(1)

k is the constant of proportionality

$I = \int\limits {J} \, dS$

$I = J \int\limits \, dS$ ........(2)

substituting (1) into (2)

$I = \frac{k}{s} \int\limits\, dS$

$I = k \int\limits^a_0 \frac{1}{s} {s} \, dS$

$I = 2\pi k\int\limits\, dS$

$I = 2\pi ka$

$k = \frac{I}{2\pi a}$

substitute $J = \frac{k}{s}$

$J = \frac{I}{2\pi as}$

7 0

3 years ago