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Simora [160]
3 years ago
11

In the field of chemistry, standard temperature and pressure conditions are:

Chemistry
2 answers:
soldi70 [24.7K]3 years ago
8 0

Answer : The correct options are, 1 atm pressure and 273 K temperature.

Explanation :

STP : STP stands for standard temperature and pressure.

At STP,

The temperature is, 0^oC or 273K or 32^oF

The pressure is, 1atm or 101.325kPa  or 760mmHg

The volume is, 22.4 L

Hence, the correct options are, 1 atm pressure and 273 K temperature.

rjkz [21]3 years ago
3 0

Standard Temperature and Pressure (STP) conditions are:


1) 760 mmHg

2) 1 atm

3) 273.15 K (0 C, 32 F)


I'm not too sure if you mistyped your first bullet, but if you did not, it is not included as an STP condition - it must be millimeters.

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I think the land for it represents a DUNE
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What are the horizontal (from left to right) parts of the periodic table called?
Setler [38]

Answer:

The correct answer is periods. See the explanation below, please.

Explanation:

The horizontal lines in the periodic table are called periods (ranging from 1 to 7) and vertical lines (ranging from 1 to 18).

The period that an element belongs to coincides with the last electronic layer of the element (that compound in period 3 will have 2 electronic layers).

8 0
4 years ago
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A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container i
Dennis_Churaev [7]

Answer:

1.33 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

<em>(P₁V₁) = (P₂V₂)</em>

<em></em>

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

  • Applying in the above equation

(P ₁V₁) = (P₂V₂)

<em>∴ V₂ = P ₁V₁/P₂</em> = (2.0 atm)(4.0 L)/(6.0 atm) =<em> 1.33 L.</em>

4 0
3 years ago
After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?
Bond [772]
Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value.  The equation to describe the decay is
Nt=N0(1/2) ^{t/t(1/2)}  where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time.  So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days
5 0
3 years ago
ΚΕ:<br> m.22<br> 2<br> What is the kinetic energy of 10kg dog running with a velocity of 12m/s?
BigorU [14]

Answer:

The answer is

<h2>720 Joules</h2>

Explanation:

The kinetic energy of a body can be found by using the formula

<h3>K.E =  \frac{1}{2}  {mv}^{2}</h3>

where

m is the mass

v is the velocity / speed

From the question

mass = 10 kg

velocity = 12 m/s

Substitute the values into the above formula and solve

That's

<h3>KE =  \frac{1}{2}  \times 10 \times  {12}^{2}  \\   = 5 \times 144  \:  \:</h3>

We have the final answer as

<h3>720 Joules</h3>

Hope this helps you

3 0
3 years ago
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