P2 = 54.6 kPa
Explanation:
Given:
V1 = 10.0 L. V2 = 50.0 L
P1 = 273 kPa. P2 = ?
We can use Boyle's law to solve this problem.
P1V1 = P2V2
Solving for P2,
P2 = (V1/V2)P1
= (10.0 L/50.0 L)(273 kPa)
= 54.6 kPa
Answer:
Sorry for the wrong answer plz
I think the answer is the number of protons.
<u>Answer:</u> The increase in temperature is 7.14°C
<u>Explanation:</u>
To calculate the change in temperature, we use the equation:

where,
q = heat absorbed = 14.5 kJ = 14500 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 485 g g
c = specific heat capacity of water = 4.184 J/g.°C
= change in temperature = ?
Putting values in above equation, we get:

Hence, the increase in temperature is 7.14°C