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morpeh [17]
3 years ago
7

Determine the nuclear radius (in fm) for each of the following nuclei.

Physics
1 answer:
tekilochka [14]3 years ago
4 0

Answer:

(a) 2.75 fm

(b) 2.89 fm

(c) 4.70 fm

(d) 7.12 fm

Explanation:

For a given element, the radius r of its nuclei is given by;

r = r₀A^{(1/3)}

Where;

A = Atomic mass of the element

r₀ = 1.2 x 10⁻¹⁵m = 1.2fm

Now let's solve for the given elements

(a) ¹²₆C

Carbon element => This has an atomic mass number of 12

Therefore its radius is given by;

r = 1.2  x 12^{1/3}

r = 1.2 x 2.29

r = 2.75 fm

(b) ¹⁴₇N

Nitrogen element => This has an atomic mass number of 14

Therefore its radius is given by;

r = 1.2  x 14^{1/3}

r = 1.2 x 2.41

r = 2.89 fm

(c) ⁶⁰₂₇Co

Cobalt element => This has an atomic mass number of 60

Therefore its radius is given by;

r = 1.2  x 60^{1/3}

r = 1.2 x 3.92

r = 4.70 fm

(d) ²⁰⁸₈₂Pb

Lead element => This has an atomic mass number of 208

Therefore its radius is given by;

r = 1.2  x 208^{1/3}

r = 1.2 x 5.93

r = 7.12 fm

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How much would a 75kg man weigh due to the effect of gravity
Nezavi [6.7K]

Answer: 735 N

Explanation:

Weight W is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass m of the body by the acceleration of gravity g:  

W=m.g

In the case of our planet Earth, the acceleration due gravity is g=9.8 m/s^{2}. So for a man whose mass is m=75 kg, his weight is:

W=(75 kg)(9.8 m/s^{2})

W=735 N

4 0
3 years ago
If a 100N weight sits in an express elevator what will be the weight when the elevator is traveling at a constant speed
yarga [219]
This is a "trick" question.

If the elevator is traveling at constant speed, it means it is at rest. This means anything inside the elevator traveling at constant speed, weights the same as in an elevator not moving -also at rest-.

So the 100N weight's weight doesn't change in an elevator traveling at constant speed.
4 0
3 years ago
A car traveling on a flat (unbanked) circular track accelerates uniformly from rest with a tangential acceleration of 1.7 m/s^2.
Komok [63]

Answer:

The coefficient of static friction between the car and the track

u=0.572

Explanation:

We don't know the mass of the car or any other information so the acceleration is the reason to solve the friction coefficient

∑F=F_{f}=m*a_{t}

As we know

F_{f}=u*F_{N}=u*m*g

Also the center ward direction forces

F_{fc}=m*a_{c}

a_{c}=\frac{v_{t}^2}{r}

F_{fc}=m*\frac{v_{t}^2}{r}

But now vt relation with the tangential acceleration

v_{t}=2*a_{t}*\frac{\pi }{r}

replacing

F_{fc}=m*a_{t}*\frac{2\pi*r}{2r}

F_{fc}=m*a_{t}*\pi

So magnitude of the force can get by

F_{f}=\sqrt{(m*a_{t}*\pi)^{2}+(m*a_{t})^{2}}

Get the factor to simplify

F_{f}=a_{t}*m*\sqrt{(1+\pi^2)}

u*m*g=m*a_{t}*(\sqrt{1+\pi^2})

Solve to u'

u=\frac{a_{t}}{g}*(\sqrt{1+\pi^2})

u=\frac{17\frac{m}{s^2} }{9.8\frac{m}{s^2}}*(\sqrt{1+\pi^2})=0.572

5 0
3 years ago
Kelly sits on a rock. Her weight is an action force. What is the reaction force?
Dmitrij [34]
The force ffrom the ground that holds the rock up and prevents her from falling through the gound, unless the ground breaks.
4 0
3 years ago
The period of a wave is the reciprocal of its ______________.
Hunter-Best [27]
Frequency

hope it helps !  
6 0
3 years ago
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