Answer:
I think it's A but I'm not sure
Explanation:
The given data is as follows.
Charge (q) = 2 coulomb, Force (F) = 60 N
Now, it is known that the relation between electric field, force and charge is as follows.
Magnitude of electric field (E) = ![\frac{Force}{charge}](https://tex.z-dn.net/?f=%5Cfrac%7BForce%7D%7Bcharge%7D)
Hence, putting the given values into the above formula as follows.
Electric field (E) = ![\frac{Force}{charge}](https://tex.z-dn.net/?f=%5Cfrac%7BForce%7D%7Bcharge%7D)
= ![\frac{60 N}{2 C}](https://tex.z-dn.net/?f=%5Cfrac%7B60%20N%7D%7B2%20C%7D)
= 30 N/C
Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.
Answer:No
Explanation: No, If forces are being applied to the object the object will not remain at rest.
You would have to subtract the mass number with atomic number which will give you 119 number of neutrons.
Answer:
Self- Actualization
Explanation:
Understanding your talents and what you can do.