Answer:
(4x^2 +9)(4x^2-9) =0
Step-by-step explanation:
16x^4 - 18 = 0
Rewriting
(4x^2)^2 - 9^2 =0
We notice that this is the difference of squares
a^2 - b^2 = (a-b)(a+b)
(4x^2 -9)(4x^2+9) =0
Answer:
31 is greater than 28
Step-by-step explanation:
That is how you read it: 31 is greater than 28
I can’t seen the question so it is hard to answer
Answer:
46
Step-by-step explanation:
Let
represent a number with
in the ten's position and
is the one's position.
This means
actually has value of
.
We are given the sum of those digits of
is 10; this means
.
It says if 18 is added to the number
, then the result is
.
So
has value
and
has value
.
We are given then:


Subtract
on both sides:

Simplify:

Subtract
on both sides:


Divide both sides by 9:

Rearrange by commutative property:

So the system of equations we want to solve is:


-------------------------Add equations together (this will eliminate the variable
and allow you to go ahead and solve for
:


Divide both sides by 2:

Simplify:

If
and
, then
.
since 4+6=10.
So the original number is (46).
18 more than 46 is 18+46=(64) which is what we wanted.
We also have the sum of 4 and 6 is 10 as well.