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daser333 [38]
3 years ago
11

Plz help me asap

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

Y=4 C=-7

Step-by-step explanation:

Solve for Y

y-7=-3

add 7 on both sides to clear the 7

y-7+7=-3+7

add

y=4

c-8=-15

clear the 8 by adding to both sides

c+8-8=-15+8

subtract

c=-7

Hunter-Best [27]3 years ago
6 0
Here you go hope this helps!

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Answer:

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Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

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         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

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   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

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If we divide through with (2) and each entity move to the opposite side; we have:

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= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

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= 126.0223095 in²

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