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ryzh [129]
3 years ago
7

a young child standing in the aisle of a parked bus tosses a ball straight up in the air and lets it drop at her feet. If instea

d the bus is moving at a constant speed of 30 km/h straight down the street and the child tosses the ball up in the air and lets it drop, where will the ball land? Why?
Physics
1 answer:
Shalnov [3]3 years ago
3 0

When the bus was at rest the ball landed at the child's feet.

Now, when the bus is moving at a constant velocity and the ball will again land at the child's feet

Reason:

The relative velocity of the child and the ball with respect of the bus is zero because they both are part of the same bus and are moving with the bus with same speed and in the same direction. Hence, There is no horizontal velocity of the ball with respect to the child. So, the ball will go vertically up with respect to the child and will land at the child's feet.

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you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.

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A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
alukav5142 [94]

Answer:

The change  in momentum is  \Delta p =   kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  =

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F =  N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p =  * (22.9 - 22.6)

            \Delta p =  * (0.3)  

              \Delta p =   kg \cdot m/s        

 

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The slope represents the acceleration
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