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timofeeve [1]
2 years ago
13

Someone please answer this, ill give you brainliest and your getting 100 points.

Physics
1 answer:
Aleks04 [339]2 years ago
4 0

Explanation:

The inner part of earth is mainly of two parts

  1. Mantal
  2. Core

Mantal and core both consists of Hot magmas .

So volcanism is required

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Describe metallurgy. Check all that apply.
mylen [45]

Answer:

A, C, D

Explanation:

got it right

7 0
3 years ago
 explain why earths acceleration is usually very small compared to the acceleration of the object the earth interact with
Marianna [84]

Answer:

F-ma

Explanation:

If you are speaking of objects like satellites, etc. then their mass is much less than that of the Earth. A good approximation is Newton's first law of motion:

Force = Mass ×  Acceleration

often written:

F = m a

The gravitational force is the same between the Earth and the object - only the mass differs. So the acceleration is inversely proportional to the mass.

6 0
2 years ago
What is the lens equation?
Strike441 [17]
The lens equation gives d relation between focal length, object distance n image distance.

1/f = 1/v + 1/u

seldon
7 0
2 years ago
Read 2 more answers
A skateboarder with a mass of 60 kg moves with a force of 20 N. What is her acceleration?
Zanzabum

Explanation:

Solution,

  • Mass(m)= 60 kg
  • Force (F)= 20 N
  • Acceleration (a)= ?

We know that,

  • F=ma
  • a=F/m
  • a=20/60
  • a=0.333 m/s²

So, her acceleration is 0.333 m/s².

4 0
2 years ago
Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ba
mars1129 [50]

Given Information:

Pendulum 1 mass = m₁ = 0.2 kg

Pendulum 2 mass = m₂ = 0.6 kg

Pendulum 1 length = L₁ = 5 m

Pendulum 2 length = L₂ = 1 m

Required Information:

Affect of mass on the frequency of the pendulum = ?

Answer:

The mass of the ball will not affect the frequency of the pendulum.

Explanation:

The relation between period and frequency of pendulum is given by

f = 1/T

The period of pendulum is given by

T = 2π√(L/g)

Where g is the acceleration due to gravity and L is the length of the string

As you can see the period (and frequency too) of pendulum is independent of the mass of the pendulum. Therefore, the mass of the ball will not affect the frequency of the pendulum.

Bonus:

Pendulum 1:

T₁ = 2π√(L₁/g)

T₁ = 2π√(5/9.8)

T₁ = 4.49 s

f₁ = 1/T₁

f₁ = 1/4.49

f₁ = 0.22 Hz

Pendulum 2:

T₂ = 2π√(L₂/g)

T₂ = 2π√(1/9.8)

T₂ = 2.0 s

f₂ = 1/T₂

f₂ = 1/2.0

f₂ = 0.5 Hz

So we can conclude that the higher length of the string increases the period of the pendulum and decreases the frequency of the pendulum.

3 0
2 years ago
Read 2 more answers
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