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timofeeve [1]
3 years ago
13

Someone please answer this, ill give you brainliest and your getting 100 points.

Physics
1 answer:
Aleks04 [339]3 years ago
4 0

Explanation:

The inner part of earth is mainly of two parts

  1. Mantal
  2. Core

Mantal and core both consists of Hot magmas .

So volcanism is required

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In a young's double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe i
dem82 [27]

Answer:

(d/λ) = 17.67

Explanation:

Equation for double-slit:

d*sinθ = m*λ

Rearrange the equation

(d/λ) = m/(sinθ)

Since it is at the second dark fringe, m = 2

Therefore:

(d/λ) = 2/(sin(6.5)

(d/λ) = 17.67

6 0
3 years ago
Three arrows are shot horizontally. They have left the bow and are traveling parallel to the ground. Air resistance is negligibl
timurjin [86]

Answer:

F₁ = F₂ = F₃ = 0 N

Explanation:

given,

Arrow 1 mass = 80 g   speed = 10 m/s

Arrow 2 mass = 80 g   speed = 9 m/s

Arrow 3 mass = 90 g   speed = 9 m/s

Horizontal Force:- F₁ , F₂ and F₃

There is no air resistance.

If Air resistance is zero then the horizontal acceleration of the arrow also equal to zero.

We know,

According to newton's second law

        F = m a

If Acceleration is equal to zero

Then Force is also equal to zero.

Hence, F₁ = F₂ = F₃ = 0 N

4 0
3 years ago
9.80 1. The density of mercury is 13600 kg/m³. What is this value in g/cm³? 2. Find the mass of water which will fit in a large
My name is Ann [436]

Answer:

1. 13..6 grams per centimeters cubed.

2. Mass = 400kg

3. Volume = 200cm = 2m

Explanation:

1. The conversion for kg/m^3 to g/cm^3 is divide by 1000.

2. density=\frac{mass}{volume}

1000=\frac{mass}{2 * 1 * 0.2}

1000*0.4=mass

400kg = mass

3. density=\frac{mass}{volume}

0.6=\frac{120}{volume}

volume=\frac{120}{0.6}

volume= 200cm

4 0
2 years ago
A 150 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. Calculate the magn
xenn [34]

Answer:

T = 2010 N

Explanation:

m = mass of the uniform beam = 150 kg

Force of gravity acting on the beam at its center is given as

W = mg

W = 150 x 9.8

W = 1470 N

T = Tension force in the wire

θ = angle made by the wire with the horizontal =  47° deg

L = length of the beam

From the figure,

AC = L

BC = L/2

From the figure, using equilibrium of torque about point C

T (AC) Sin47 = W (BC)

T L Sin47 = W (L/2)

T Sin47 = W/2

T Sin47 = 1470

T = 2010 N

6 0
3 years ago
Find the kinetic energy of an electron whose de broglie wavelength is 34.0 nm.
dezoksy [38]
The De Broglie wavelength of the electron is
\lambda=34.0 nm=34 \cdot 10^{-9} m
And we can use De Broglie's relationship to find its momentum:
p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s

Given p=mv, with m being the electron mass and v its velocity, we can find the electron's velocity:
v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}=  2.13 \cdot 10^4 m/s

This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula:
K= \frac{1}{2}mv^2= \frac{1}{2}(9.1 \cdot 10^{-31} kg)(2.13 \cdot 10^4 m/s)^2=2.06 \cdot 10^{-22} J
3 0
3 years ago
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