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3 years ago

In the chemistry laboratory why do scientists use a mortal and pestle

1 answer:

4 0

To increase surface area of a solute.
The mortar and pestle can make the solute from bulk to powder. 
So the surface area will increase and the reaction rate or dissolving rate will also increase.

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Give two reasons why the flame test is sometimes invalid

zlopas [31]

The two reason behind the invalidity of flame test are false positive and false negative.
while performing the flame test you must have to be accurate otherwise you will get false results may be positive for some element or may be negative in case the element is present. The main reason to get the false positive and false negative is the presence and contamination of sodium.

6 0

3 years ago

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This chart shows descriptions of the atoms for four different substances.

Whitepunk [10]

I think it’s Object 3
Hopefully this helps

8 0

3 years ago

Subject: Chemistry whoever does this right will give the brainliest <3)

Andru [333]

Answer:

1 A

3 main types of bond are

Ionic bond ( formed due to complete transfer of electron between atoms(

Covalent bond ( formed by mutual sharing of electron)

Metalic bond ( present in the metals due to mobile electrons)

1 B bond in CaO is ionic bond formation in attached image

1 C hydrogen bond with nitrogen is covelent NH3 ammonia is formed because a bond between two non metals is expected to be covalent

More their electronegativity difference between hydrogen and nitrogen is less than 1.7 that makes it covalent

Explanation:

4 0

3 years ago

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Which of the following phases of matter has a fixed shape and volume

kodGreya [7K]

A matter in the solid phase has a fixed shape and volume.

4 0

3 years ago

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What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

8 0

3 years ago