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quester [9]
4 years ago
5

How does a forest fire model the energy flow of fuel combustion?

Chemistry
1 answer:
disa [49]4 years ago
5 0

Answer:

Explanation:

Combustion can be defined as the burning of a compound in the presence of oxygen to produce carbon dioxide and water. Because it involves the release of heat (energy), it is referred to as an exothermic reaction.

Fuel is an <u>organic compound</u> and it's combustion will also go through the process above and also <u>releases heat (exothermic reaction)</u> into the atmosphere after burning. However, same can be said about forest fire also; as the forest is made up of plants (whose major <u>constituents are organic </u>also). The forest fire can also be termed as combustion because it burns in the presence of oxygen, <u>releasing heat (energy) into the atmosphere</u> (which also makes it an <u>exothermic reaction</u>).

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Determine the frequency and wavelength (in nm) of the light obsorded when the e- goes from n=1 to n=5
morpeh [17]

Answer:

Frequency = 3.16 ×10¹⁴ Hz

λ = 0.95×10² nm

Explanation:

Energy associated with nth state is,

En =  -13.6/n²

For n = 1

E₁ = -13.6 / 1²

E₁ = -13.6/1

E₁ = -13.6 ev

Kinetic energy of electron = -E₁ = 13.6 ev

For n = 5

E₅ = -13.6 / 5²

E₅ = -13.6/25

E₅ = -0.544 ev

Kinetic energy of electron = -E₅ = 0.544 ev

Wavelength of radiation emitted:

E = hc/λ = E₅ - E₁

hc/λ = E₅ - E₁

by putting values,

6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.544ev  - (-13.6 ev  )

6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 13.056 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /13.056 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /13.056 × 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 13.056 × 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 20.9 ×10⁻¹⁹ J

λ = 0.95×10⁻⁷ m

m to nm:

0.95×10⁻⁷ m ×10⁹nm/1 m

0.95×10² nm

Frequency:

Frequency = speed of electron / wavelength

by putting values,

Frequency = 3×10⁸m/s /0.95×10⁻⁷ m

Frequency = 3.16 ×10¹⁴ s⁻¹

s⁻¹ = Hz

Frequency = 3.16 ×10¹⁴ Hz

4 0
3 years ago
2 FONS
stiv31 [10]

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4)  = F1/4

7 0
3 years ago
A sample of sodium reacts completely with 0.213 kgkg of chlorine, forming 351 gg of sodium chloride. What mass of sodium reacted
lapo4ka [179]

Answer:

The mass of sodium reacted is 138 grams

Explanation:

Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.

Na = sodium

Cl2 = chlorine gas

Na + Cl2 → NaCl

The balanced equation is

2Na(s) + Cl2(g) → 2NaCl(aq)

Atomic mass of sodium = 23 grams per mol

Atomic mass of chlorine = 35.5 grams per mol

From the chemical equation the molar mass are as follows

Sodium = 2 × 23 = 46 grams

Chlorine = 35.5 × 2 = 71 grams

Sodium chloride =  2 × 23 + 2 × 35.5 = 117 grams

if 46 grams sodium reacted to produce 117 grams of sodium chloride

? grams of sodium react to produce 351 grams sodium chloride

grams of sodium reacted = (351 × 46)/117

grams of sodium reacted = 16146/117

grams of sodium reacted = 138  grams

6 0
3 years ago
Read 2 more answers
For which of the reactions listed below will Gibbs free energy always be
Vanyuwa [196]

Answer:

an exothermic reaction that Increase in entropy

3 0
3 years ago
Read 2 more answers
two solutions are boiled. the first is 1 mol of a sodium chloride(nacl) solution forming two ions. the second one is 1 mol of ca
svet-max [94.6K]
It will be different according to how each of them is easily warmed up when using thermal energy. 
Water heats at 100 celsius and all the other solutions have slightly different boiling points

4 0
4 years ago
Read 2 more answers
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