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Arturiano [62]
3 years ago
5

why can't scientists collect temperature and volume data for an enclosed gas at temperatures near absolute zero.

Chemistry
2 answers:
stich3 [128]3 years ago
5 0

Answer:

Because a phenomenon called Bose-Einstein condensation can occur.

Explanation:

Bose-Einstein condensation is a phenomenon that can occur when a scientist works with temperatures close to absolute zero. In this situation, the material being analyzed is compacting, condensing, in a way that could become a large, single atom. When this happens, it is impossible to collect accurate temperature and volume data. This phenomenon occurs in the processes of temperature decay and physical state changes, in which the gas becomes liquid, the liquid becomes solid, and, in this way, the solid would tend to have its particles more and more united.

sergeinik [125]3 years ago
3 0
Absolute zero is measured in kelvin and kelvin is -324 degree celsius witch turns most elements turn solid
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The answer is 8. atomic number: the number of protons in the nucleus of an atom.
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Enter a balanced nuclear equation for the production of lead-212, used in the treatment of some cancers, from the beta decay of
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Explanation:

Beta emission involves the conversion of a neutron to a proton, an electron and a neutrino. This leads to a reduction in the neutron-proton ratio.

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3 years ago
Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +
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<u>Answer:</u>

<u>For 1:</u> The value of \Delta G for the chemical equation is -24.636 kJ/mol

<u>For 2:</u> The value of \Delta G for the chemical equation is -20.925 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)

  • <u>For 1:</u>

To calculate the \Delta G for given value of equilibrium constant, we use the relation:

\Delta G=-RT\ln K_p      .....(1)

where,

\Delta G = ? kJ/mol

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of \Delta G for the chemical equation is -24.636 kJ/mol

  • <u>For 2:</u>

The expression of K_p for the given chemical equation is:

K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}

We are given:

p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm

Putting values in above equation, we get:

K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52

Now, calculating the value of \Delta G by using equation 1:

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of \Delta G for the chemical equation is -20.925 kJ/mol

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4 years ago
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<span>D) recycling ;)


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A sample of an uranium compound is found to be losing mass gradually. Explain what is happening to the sample.​
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Answer:

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Explanation:

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