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laila [671]
3 years ago
13

Explain The Basic Difference Between Bs2 And Bs3 Engine.​

Engineering
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

The main difference between the bs2 and bs3 engine is to present in the catalytic converter. And in bs2 engines the catalytic converter is does not used for the formation of hc and co. In bs3 engine there is no harmful emissions in the hc and co

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Two gage marks are placed exactly 250 mm apart on a 12-mm-diameter aluminum rod with E 5 73 GPa and an ultimate strength of 140
NNADVOKAT [17]

Answer:

81.76 N/mm² ( MPa), 1.71233

Explanation:

Modulus of elasticity = stress / strain

stress = modulus of elastic × strain

strain = ΔL / L = 250.28 mm - 250 mm / 250 mm = 0.00112

Modulus of elasticity E = 73 GPa = 73 × 10³ MPa where 1 MPa = 1 N/mm²

E = 73 × 10³N/mm²

stress =  73 × 10³N/mm²× 0.00112 = 81.76 N/mm² ( MPa)

b) Factor of safety = maximum allowable stress / induced stress = 140 MPa / 81.76 MPa = 1.71233

8 0
4 years ago
Need help with these 3 questions pls help
Burka [1]

Answer:

Explanation:

First one is passion i think

second one is true im not sure

Third one is Time managaemant

Hope this helps!

8 0
3 years ago
An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate (ϵ˙) is found to be
cupoosta [38]

Answer:

Activation energy for creep in this temperature range is Q = 252.2 kJ/mol

Explanation:

To calculate the creep rate at a particular temperature

creep rate, \zeta_{\theta} = C \exp(\frac{-Q}{R \theta} )

Creep rate at 800⁰C, \zeta_{800} = C \exp(\frac{-Q}{R (800+273)} )

\zeta_{800} = C \exp(\frac{-Q}{1073R} )\\\zeta_{800} = 1 \% per hour =0.01\\

0.01 = C \exp(\frac{-Q}{1073R} ).........................(1)

Creep rate at 700⁰C

\zeta_{700} = C \exp(\frac{-Q}{R (700+273)} )

\zeta_{800} = C \exp(\frac{-Q}{973R} )\\\zeta_{800} = 5.5 * 10^{-2}  \% per hour =5.5 * 10^{-4}

5.5 * 10^{-4}  = C \exp(\frac{-Q}{1073R} ).................(2)

Divide equation (1) by equation (2)

\frac{0.01}{5.5 * 10^{-4} } = \exp[\frac{-Q}{1073R} -\frac{-Q}{973R} ]\\18.182= \exp[\frac{-Q}{1073R} +\frac{Q}{973R} ]\\R = 8.314\\18.182= \exp[\frac{-Q}{1073*8.314} +\frac{Q}{973*8.314} ]\\18.182= \exp[0.0000115 Q]\\

Take the natural log of both sides

ln 18.182= 0.0000115Q\\2.9004 = 0.0000115Q\\Q = 2.9004/0.0000115\\Q = 252211.49 J/mol\\Q = 252.2 kJ/mol

3 0
3 years ago
Which of these energy technologies does not rely on a generator to produce electricity?
Phantasy [73]

<u>Wind turbine</u> does not rely on a generator to produce electricity. Thus, the correct option is option A.

<h3>What is a generator?</h3>

A generator is a device used in the production of electricity that transforms motive power, which is mechanical energy, or fuel-based power, which is chemical energy, into electric power for use in an external circuit.

Steam turbines, gas turbines, water turbines, internal combustion engines, wind turbines, and even hand cranks can all be used to generate mechanical energy. Michael Faraday, a British scientist, created the Faraday disk, the first electromagnetic generator, in 1831. For electric power grids, generators supply almost all of the energy.

Photovoltaic and fuel cell powered generators, in addition to electromechanical designs, use solar power and hydrogen-based fuels, respectively, to produce electrical output.

Learn more about generators

brainly.com/question/4330859

#SPJ4

8 0
1 year ago
Which of the following is the LEAST-Likely cause of tire wear? A) Underinflation B) Braking C) Acceleration D) Tire rotation
mihalych1998 [28]

Answer:

Tire rotation is the least likely cause of tire wear. So, the option D is correct.

Explanation:

Step1

Under-inflation is the process of tire failure under low pressure. This contributes the wear on tire.

Step2

On breaking, kinetic energy changes to heat energy because of rubbing of tire. So, rubbing action increases the wear on the tire.

Step3

Acceleration on the vehicle increases the rubbing action as well as the wear and tear on the tire. So, acceleration is an also a major cause of tire wear.

Step4

Tire rotation has least amount of wear and tear due to no rubbing action.  It has less amount surface contact with the surface in rotation.  

Thus, tire rotation is the least likely cause of tire wear. So, the option D is correct.  

4 0
3 years ago
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