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Snezhnost [94]
2 years ago
8

You will be observing laminar-turbulent transition for room temperature (about 20°C) water flowing in a 0.602"" ID pipe (Schedul

e 40 1/2"" pipe). Estimate the flow rate in gallons/minute (gpm) at which transition should begin (ReD= 2300) and the flow rate for fully turbulent flow (ReD> 4000). Repeat calculations for a 0.804"" ID pipe (Schedule 40 3/4"" pipe).

Engineering
1 answer:
igomit [66]2 years ago
8 0

Answer:

b) 0.7667gallons/minutes

Explanation:

check the attachment below for other answers

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An aluminum block weighing 28 kg initially at 140°C is brought into contact with a block of iron weighing 36 kg at 60°C in an in
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Answer:

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Solution:

As per the question:

Mass of the Aluminium block, M = 28 kg

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Mass of Iron block, m = 36 kg

Temperature for iron block, T_{i} = 60^{\circ}C = 273 + 60 = 333 K

At 400 k

Specific heat of Aluminium, C_{p} = 0.949\ kJ/kgK

At room temperature

Specific heat of iron, C_{p} = 0.45\ kJ/kgK

Now,

To calculate the final equilibrium temperature:

Amount of heat loss by Aluminium = Amount of heat gain by Iron

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Thus

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T_{e} = Equilibrium temperature

Now,

To calculate the changer in entropy:

\Delta s = \Delta s_{a} + \Delta s_{i}

Now,

For Aluminium:

\Delta s_{a} = MC_{p}ln\frac{T_{e}}{T_{i}}

\Delta s_{a} = 28\times 0.949\times ln\frac{382.71}{413} = - 2.025\ kJ/K

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\Delta s_{i} = mC_{i}ln\frac{T_{e}}{T_{i}}

\Delta s_{a} = 36\times 0.45\times ln\frac{382.71}{333} = 2.253\ kJ/K

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\Delta s =-2.025 + 2.253 = 0.228\ kJ/K

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