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timurjin [86]
3 years ago
6

A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 N and 1510 N, respectively. Th

e acceleration of the cable is 0.620 m/s^2, upward. What is the tension in the cable above the worker (the worker is above the crate, not touching it)?
Physics
1 answer:
GuDViN [60]3 years ago
4 0
Since resultant force = mass * acceleration, T-2475 = 0.620*mass
mass = \frac{2475}{9.8} = 252.5...
therefore T=(0.620*252.5...)+2475=2631.55... = 2630N (3sf)
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Complete Question

The complete question is shown on the first and second uploaded image

Answer:

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=>  nRT [lnV]   | \left \ {V_f}} \atop {V_o}} \right.

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From the question \frac{V_f}{V_o }  =  R_v

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at initial  state

W_c =  P_o V_o ln (R_v)  

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