1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shkiper50 [21]
3 years ago
12

Solid sodium metal reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrog

en are formed when 35 g of sodium are added to water? Please show work.

Chemistry
1 answer:
asambeis [7]3 years ago
5 0

Answer:

4.6 × 10²³ molecules:

Step-by-step solution

You will need a balanced equation with masses, moles, and molar masses, so let's gather the information in one place:

M_r:  22.99

          2Na + 2H₂O ⟶ 2NaOH + H₂

m/g:    35

1. Calculate the <em>moles of Na </em>

Moles of Na = 35 g Na × (1 mol Na/22.99 g Na)

Moles of Na = 1.52 mol Na

2. Calculate the <em>moles of H₂ </em>

Moles of H₂ = 1.52 mol Na × (1 mol H₂/2 mol Na)

Moles of H₂= 0.761 mol H₂

3. Calculate the molecules of H₂

6.022 × 10²³ molecules H₂ = 1 mol H₂

                Molecules of H₂ = 0.761 × (6.022 × 10²³ /1)

                Molecules of H₂ = 4.6 × 10²³ molecules H₂

The reaction forms 4.6 × 10²³ molecules of H₂.

You might be interested in
If you have a 1500 g aluminum pot, how much heat energy is needed to raise its temperature by 100°C?
Nataly [62]

The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.

The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

Explanation:

The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.

So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).

Then, the heat energy required to raise the temperature will be

q = m*c*del T = 1500 * 0.900 * 100 = 135000 = 135 kJ

Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.

Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100  °C.

Then, the heat energy required to raise its temperature will be

q = m*c*del T = 1500 * 0.385 * 100 = 57750 = 57.75 kJ

And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.

So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

8 0
3 years ago
Plz answer all 3, I will give 5 stars and brainiest!!! :)<br><br> THANKS
Cerrena [4.2K]

Answer:

B. Positive charge is caused by lack of electrons. A positive ion is formed by the loss of negatively charged electrons. Although the number of protons does not change in the ion, there is an excess number of protons over electrons which produces the positive charge. All electrons in the outer energy level are lost.

C. If there are more electrons than protons, then the element is a negative ion. The amount of neutrons does not play a factor into making a difference between an atom or an ion.

Explanation:

please give brainliest. :)

and have a great day!

5 0
3 years ago
Determine the number of protons and neutrons in plutonium-239 and write its symbol in the form azx.
Verizon [17]
94 protons and 145 neutrons
4 0
2 years ago
Read 2 more answers
The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days
professor190 [17]

Answer:  

6.2 g  

Explanation:  

In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is  

N = \frac{N_{0}}{2^{n}}  

where  

<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance  

1. Calculate the <em>number of half-lives</em>.  

If t_{\frac{1}{2}} = \text{3.8 da}  

n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}

2. Calculate the <em>final mass</em> of the substance.  

\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}

4 0
3 years ago
Select the correct formula for the polyatomic ion.
Helga [31]
The poly atomic ion formula for ammonium would be NH4+
7 0
3 years ago
Read 2 more answers
Other questions:
  • Ammonia forms when hydrogen gas reacts with nitrogen gas according to the equation below. If equal moles of nitrogen and hydroge
    8·2 answers
  • If a gaseous mixture is made by combining 2.74 g Ar 2.74 g Ar and 4.90 g Kr 4.90 g Kr in an evacuated 2.50 L container at 25.0 ∘
    6·1 answer
  • When an atom loses electrons it becomes___
    11·1 answer
  • Which one is your favorite?
    9·2 answers
  • Why ions move and in which direction they move in the presence of an electric field created between two electrodes having opposi
    7·1 answer
  • Rounding to significant figures?
    9·1 answer
  • what type of reaction mechanism is operative in the conversion of 2-methyl-2-butanol into 2-chloro-2-methylbutane?
    6·1 answer
  • Select all the correct answers.
    15·1 answer
  • (pls help !!) question is in image
    7·1 answer
  • Write a reaction and balance it for the reaction of lead with hydrochloric acid
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!