Answer:
77.14 atm of pressure should be of an acetylene in the tank.
Explanation:

According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.
Moles of oxygen=
Moles of acetylene =

Volume of large tank with oxygen gas, 
Pressure of the oxygen gas inside the tank = 
..[1]
Volume of small tank with acetylene gas ,
Pressure of the acetylene gas inside the tank = 
..[2]
Considering both the gases having same temperature T, [1]=[2]



77.14 atm of pressure should be of an acetylene in the tank.
Answer:
Mg
Explanation:
Mg is above Al on the table meaning it is easier to oxidize.
Fe and Zn are below Al on the table showing they are not as reactive.
Answer:
V2= 0.0796m3
Explanation:
We have that for a real gas the following relation is fulfilled:
PV / T = constant
To use this formula I need to pass the pressure of mmHg to KPa and the volume of L to m3, knowing that
1Kpa = 7.50062mmHg
1L = 0.001m3
So i can say
P1V1/T1 =P2V2/T2
So
V2= P1V1T2/P2T1
V2= 51.60KPa*0.034m3*350k/36.53KPa*211k
finally
V2= 0.0796m3