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3 years ago

O The ester functional group is symbolized as || R-C-R True False

Chemistry

1 answer:

nevsk [136]3 years ago

4 0

Answer:

False

The ester functional group is not symbolized as R-C-R

Explanation:

The general formula of ester functional group is RCOOR′ where R represents a hydrogen atom or aryl group or an alkyl group while R' represents the alkyl group or an aryl group

Hence, the given statement is false

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A chemical formula for a molecular compound represents the composition of

Leni [432]

Answer:

A chemical formula for a molecular compound represents the composition of a molecule.

Explanation:

Chemical formulas are alphanumeric expressions that are used to indicate the composition of chemical substances. They consist of chemical symbols that indicate the elements that form a compound; The number of atoms provided by each element is also indicated by the use of a subscript, that is, a small number that is placed below and to the right of each element that so requires. When an element does not have a subscript, it is understood that there is only one atom of it in the substance.

Each molecule corresponds to a chemical formula, as well as a name according to the rules of the chemical nomenclature.

Then, a chemical formula for a molecular compound represents the composition of a molecule.

4 0

3 years ago

7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken

Nana76 [90]

Answer: The molarity of Iron (III) chloride is 0.622 M.

Explanation:

Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

$\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M$

Hence, the molarity of Iron (III) chloride is 0.622 M.

3 0

3 years ago

Question 7 (1 point)

Kamila [148]

1.Organism
2.Organ system
3.Organs
4.Tissues
5.Cell

6 0

3 years ago

Read 2 more answers

In a chemical reaction, substrate molecule A is broken down to form one molecule of product B and one molecule of product C. The

MAVERICK [17]

Answer:

The answer to your question is d. 0.5 M

Explanation:

Data

[A] = 1M

K = 0.5

Concentration of B and C at equilibrium = x

Concentration of A at equilibrium = 1 - x

Equation of equilibrium

k = $\frac{[B][C]}{A}$

Substitution

$0.5 = \frac{[x][x]}{1 - x}$

Simplification

0.5 = $\frac{x^{2}}{1 - x}$

Solve for x

0.5(1 - x) = x²

0.5 - 0.5x = x²

x² + 0.5x - 0.5 = 0

Find the roots x₁ = 0.5 x₂ = -1

There are no negative concentrations so the concentration of A at equilibrium is

[A] = 1 - 0.5

= 0.5 M

4 0

3 years ago

PLEASE HELP!! 20 POINTS!

SpyIntel [72]

It's something to do with the weathering process. Eg. At night it's really cold, and in the day it's really hot. Because the temperature keeps changing dramatically day in and day out, the sand dunes start to be sort of hacked or re-shaped, or even formed.

7 0

3 years ago

Read 2 more answers