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lesya692 [45]
3 years ago
8

O The ester functional group is symbolized as || R-C-R True False

Chemistry
1 answer:
nevsk [136]3 years ago
4 0

Answer:

False

The ester functional group is not symbolized as R-C-R

Explanation:

The general formula of ester functional group is RCOOR′ where R represents a hydrogen atom or aryl group or an alkyl group while R' represents the alkyl group or an aryl group

Hence, the given statement is false

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When 2.85 moles of chlorine reacts with excess tin, how many moles of tin(IV) chloride are formed
svp [43]
                                Sn + 2Cl2 ------> SnCl4
from reaction                2 mol            1 mol
from the problem          2.85 mol       x mol

x=2.85*1/2≈1.43 mol SnCl4
7 0
4 years ago
What is potiential and kinetic engergy? pls someone answer my question
Afina-wow [57]

Answer:

Potential Energy is stored energy or energy of position (gravitational). The object isn't moving. For example, a ball being held is potential energy because the object isn't moving but it has the potential of turning into kinetic energy.

Kinetic Energy is the energy of motion. For example, running. You are moving, and there is clear action and activity

4 0
3 years ago
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Ozone (O 3) in the atmosphere can react with nitric oxide (NO): O 3(g) + NO(g) → NO 2(g) + O 2(g). Calculate the ΔG° for this re
Mandarinka [93]

Answer:

ΔG°  = 1022. 8 kJ

Explanation:

ΔH° = –199 kJ/mol

ΔS° = –4.1 J/K·mol

T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)

ΔG° = ?

The relationship between these varriables are;

ΔG° = ΔH°  - TΔS°

ΔG° = –199 - 298 (–4.1)

ΔG° = -199 + 1221.8

ΔG°  = 1022. 8 kJ

6 0
3 years ago
300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You
Bas_tet [7]

Explanation:

It is given that volume of Pb(NO_{3})_{2} is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

            PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)

K_{sp} for PbCl_{2} is given as 1.7 \times 10^{-5}.

As, molarity is number of moles present in liter of solution.

Hence, moles of Pb^{2+}(aq) will be calculated as follows.

         moles of Pb^{2+}(aq) = 0.300 L \times 0.200 M

                                                = 0.06 mol

                      [Pb^{2+}] = \frac{0.06 mol}{0.5 L}

                                            = 0.120 M

Mole of Cl^{-}(aq) = 0.2 L \times 0.05 M  

                                  = 0.010 M

Now,   Q = [Pb^{2+}][Cl^{-}]^{2}

                  = 0.120 \times (0.010)^{2}

                  = 1.2 \times 10^{-5}    

As, Q < K_{sp} hence, there will be no formation of PbCl_{2} precipitate.

3 0
3 years ago
What does an aluminum atom become when it loses its three valence electrons? a?
Artist 52 [7]
Aluminum atomic number 13 becomes Neon with an atomic number of 10 when it loses three valence electrons.
6 0
4 years ago
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