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Dmitrij [34]
3 years ago
14

Container A holds 717 mL of ideal gas at 2.50 bar . Container B holds 179 mL of ideal gas at 4.30 bar . If the gases are allowed

to mix together, what is the partial pressure of each gas in the total volume?
Chemistry
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

Pressure gas A

using boyles law

p1}V_{1} = P_{2}V2

V2 = 717ml + 179 ml

     = 896ml

∴ P_{2} = 2.50 × 717ml/896ml

       = 2.0 bar

Pressure B

P2 = 4.30 bar× 179ml/896ml

     = 0.859bar

ptotal = P_{A}+P_{B}

          = 2.0 bar + 0.859 bar

           = 2.859 bar

           

Explanation: Using Daltons law of partial pressure,the pressure is independently of each other when the gas is exerted.where we can use daltons law to find the pressure of each gas separately when it expands into the total volume in two containers.

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4 years ago
What type of matter can be physically separated
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7 0
3 years ago
Read 2 more answers
1. a.) Calculate the wavelength of light which has a frequency of 5.25 x 10 14 Hz.
Scilla [17]
<h3>Answer:</h3>

5.71 × 10² nm

<h3>Explanation:</h3>

The product of wavelength and frequency of a wave gives the speed of the wave.

Therefore;

Velocity of wave = Wavelength × Frequency

c = f ×λ

In our case;

Frequency = 5.25 × 10^14 Hz

Speed of light = 2.998 × 10^8m/s

But;

λ = c ÷ f

  = 2.998 × 10^8m/s ÷  5.25 × 10^14 Hz

  = 5.71 × 10^-7 m

But; 1 M = 10^9 nm

Therefore;

wavelength = 5.71 × 10^-7 × 10^9

                  = 5.71 × 10² nm

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3 0
3 years ago
216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.
ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0
4 years ago
Given 0.02 of KF, how many liters of solution are needed to make a 7.2 solution?
Dmitry_Shevchenko [17]

Answer:

1/360

Explanation:

let x = liters

molarity=moles of solute/liters of solution, 7.2=0.02/x or 7.2=(1/50)(1/x), 7.2(50)=(1/x), 360(x)=1, x=1/360

7 0
3 years ago
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