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Anastasy [175]
3 years ago
14

What is the formula of the ion formed when cadmium achieves a pseudo-noble-gas electron configuration? consult the periodic tabl

e. cd2- cd+ cd3+ cd2+?
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
The correct option is "Cd²⁺".

When an element achieves pseudo noble gas configuration<span> it means it has 18 </span>electrons<span> in the highest energy level instead of 8.

The electronic configuration of cadmium is:
</span><span>1<span>s</span></span>² <span>2<span>s</span></span>² <span>2<span>p</span></span>⁶ <span>3<span>s</span></span>² <span>3<span>p</span></span>⁶ <span>4<span>s</span></span>² <span>3<span>d</span></span>¹⁰ <span>4<span>p</span></span>⁶ <span>5<span>s</span></span>² <span>4<span>d<span>1</span></span></span>¹⁰<span><span><span>
</span></span></span>

and the electron configuration of <span>C<span>d</span></span>²⁺ is

<span>1<span>s</span></span>² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

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4 0
3 years ago
A liquid has a density of 1.17 g/cm3, how many liters of the liquid have a mass of 3.75 kg
Luda [366]
<span>There are 1000 cm3 in 1 liters. Hence 1 liter of the liquid would weigh: 1000 cm3 x (1.17 g/cm3) = 1170 gm and there are 1000 gm in 1 kg, so we want enough liters to have a mass of 3.75 kg x 1000 gm/kg = 3750 gm Hence, # of liters = desired mass / # of gm per liter = 3750 gm / 1170 gm/liter = 3.2051282 liters</span>
5 0
3 years ago
Hi, someone knows how to balance the following equation, and if you can thank you if you can explain how that is done:
kari74 [83]
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2 

    LHS                          RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation. 
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O

Hope it helped!
7 0
3 years ago
A city continuously disposes of effluent from a wastewater treatment plant into a river. The minimum flow in the river is 130 m3
Vera_Pavlovna [14]

Answer:

2.54\ \text{mg/L}

Explanation:

C = Allowable concentration = 1.1 mg/L

Q_1 = Flow rate of river = 130\ \text{m}^/\text{s}

Q_2 = Discharge from plant = 37\ \text{m}^3/\text{s}

C_1 = Background concentration = 0.69 mg/L

C_2 = Maximum concentration that of the pollutant

The concentration of the mixture will be

C=\dfrac{Q_1C_1+Q_2C_2}{Q_1+Q_2}\\\Rightarrow C_2=\dfrac{C(Q_1+Q_2)-Q_1C_1}{Q_2}\\\Rightarrow C_2=\dfrac{1.1(130+37)-130\times 0.69}{37}\\\Rightarrow C_2=2.54\ \text{mg/L}

The maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant is 2.54\ \text{mg/L}.

6 0
2 years ago
11111111111111111111
Lady bird [3.3K]

Answer:

2222222222

Explanation:

mark me branliest of

5 0
3 years ago
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