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Anastasy [175]
3 years ago
14

What is the formula of the ion formed when cadmium achieves a pseudo-noble-gas electron configuration? consult the periodic tabl

e. cd2- cd+ cd3+ cd2+?
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
The correct option is "Cd²⁺".

When an element achieves pseudo noble gas configuration<span> it means it has 18 </span>electrons<span> in the highest energy level instead of 8.

The electronic configuration of cadmium is:
</span><span>1<span>s</span></span>² <span>2<span>s</span></span>² <span>2<span>p</span></span>⁶ <span>3<span>s</span></span>² <span>3<span>p</span></span>⁶ <span>4<span>s</span></span>² <span>3<span>d</span></span>¹⁰ <span>4<span>p</span></span>⁶ <span>5<span>s</span></span>² <span>4<span>d<span>1</span></span></span>¹⁰<span><span><span>
</span></span></span>

and the electron configuration of <span>C<span>d</span></span>²⁺ is

<span>1<span>s</span></span>² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

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Nikolay [14]

Answer:

\Delta H_{rxn3}=-162.5 kJ/mol

Explanation:

The reaction we need to calculate:

O_3 (g) + Cl (g) \longrightarrow ClO (g) + O_2 (g)

1) O_3 (g) + ClO (g) \longrightarrow Cl (g) +2 O_2 (g)

\Delta H_{rxn}=-122.8 kJ/mol

We need the ClO in the products side, so we use the inverse of this reaction:

Cl (g) +2 O_2 (g) \longrightarrow O_3 (g) + ClO (g)

\Delta H_{rxn1}=122.8 kJ/mol

2) 2 O_3 (g) \longrightarrow 3 O_2 (g)

\Delta H_{rxn2}=-285.3 kJ/mol

Now we need to combine this two:

Cl (g) +2 O_2 (g) + 2 O_3 (g)\longrightarrow O_3 (g) + ClO (g) + 3 O_2 (g)

Cl (g) + O_3 (g)\longrightarrow ClO (g) + O_2 (g)

The enthalpy of reaction:

\Delta H_{rxn3}=\Delta H_{rxn1}+ \Delta H_{rxn2}=122.8 kJ/mol-285.3 kJ/mol

\Delta H_{rxn3}=-162.5 kJ/mol

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3 years ago
Which pair of symbols represents a metalloid and a noble gas?(1) Si and Bi (3) Ge and Te
Natali5045456 [20]
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SCORPION-xisa [38]

Answer:

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Explanation:

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Function of beta-galactosidase side is to
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The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas is shown by which balanced chemical equation?
LekaFEV [45]
Know what decomposition is. The compound is "breaking down".

Di means 2 while, Tetra means 4.

First, we will simply follow the instructions and break down the compound as so: The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas

*Take into account that diatomic molecules (HNOFClBRI) will always have a subscript of 2

N
₂O₄⇒N₂+O₂

After breaking down the compound, we must now balance the equation.

To balance the equation, we must make sure that each element has the same amount of atoms.

Starting with compound at the left of the yield: N=2 and O=4
But, at the right of the yield: N=2 and O=2
We have now discovered that the oxygen gas is not balanced throughout the equation.

N₂O₄⇒N₂+2O₂

*We simply multiply the oxygen gas on the right of the equation by 2

After multiplying, on the right side of the equation, O=4. We now have a balanced equation because all elements have the same amount of atoms on each side.

So your final answer for this balanced decomposition chemical equation is: N₂O₄⇒N₂+O₂


6 0
4 years ago
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