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Anastasy [175]
3 years ago
14

What is the formula of the ion formed when cadmium achieves a pseudo-noble-gas electron configuration? consult the periodic tabl

e. cd2- cd+ cd3+ cd2+?
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
The correct option is "Cd²⁺".

When an element achieves pseudo noble gas configuration<span> it means it has 18 </span>electrons<span> in the highest energy level instead of 8.

The electronic configuration of cadmium is:
</span><span>1<span>s</span></span>² <span>2<span>s</span></span>² <span>2<span>p</span></span>⁶ <span>3<span>s</span></span>² <span>3<span>p</span></span>⁶ <span>4<span>s</span></span>² <span>3<span>d</span></span>¹⁰ <span>4<span>p</span></span>⁶ <span>5<span>s</span></span>² <span>4<span>d<span>1</span></span></span>¹⁰<span><span><span>
</span></span></span>

and the electron configuration of <span>C<span>d</span></span>²⁺ is

<span>1<span>s</span></span>² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

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The molar mass of NH3 is 17.03 g/mol. The molar mass of H2 is 2.0158 g/mol. In a particular reaction, 0.575 g of NH3 forms. What
Arlecino [84]

The balanced chemical reaction is:

N2 + 3H2 = 2NH3

 

We are given the amount of ammonia formed from the reaction. This is where we start our calculations.

 

0.575 g NH3 (1 mol NH3 / 17.03 g NH3) (3 mol H2 / 2 mol NH3) ( 2.02 g H2 / 1 mol H2) = 0.10 g H2

3 0
3 years ago
Read 2 more answers
1.50μm2. Convert this to square meters.
Verizon [17]
1.50x10^6 m2 is the answer you're looking for 
6 0
3 years ago
to find the density of stopper I weighted it and found its mass to 4.8g. After that I filled a graduated cylinder with 32.1mL of
Fynjy0 [20]

Answer:

0.68g/ml

Explanation:

The density of an object is its mass per unit volume. It is calculated using the formula

Density = mass / volume

Mass of stopper weighed = 4.8g

The volume of stopper can be got by subtracting the (volume of water) from the (volume of water+stopper) i.e.

= 39.2ml - 32.1ml

= 7.1ml

Volume of stopper = 7.1ml

Density of stopper= 4.8/7.1

Density= 0.676056

Therefore, the density of the stopper is 0.68g/ml

4 0
3 years ago
How does the behavior of a high-energy particle compare to a low-energy particle?
irina1246 [14]

Answer:

The problem of energy exchange between waves and particles, which leads to energization of the latter, in an unstable plasma typical of the radiation belts. The ongoing Van Allen Probes space mission brought this problem among the most discussed in space physics. A free energy which is present in an unstable plasma provides the indispensable condition for energy transfer from lower energy particles to higher-energy particles via resonant wave-particle interaction. This process is studied in detail by the example of electron interactions with whistler mode wave packets originated from lightning-induced emission. We emphasize that in an unstable plasma, the energy source for electron energization is the energy of other particles, rather than the wave energy as is often assumed. The way by which the energy is transferred from lower energy to higher-energy particles includes two processes that operate concurrently, in the same space-time domain, or sequentially, in different space-time domains, in which a given wave packet is located. In the first process, one group of resonant particles gives the energy to the wave. The second process consists in wave absorption by another group of resonant particles, whose energy therefore increases. We argue that this mechanism represents an efficient means of electron energization in the radiation belts.

Explanation:

Fun facts:

In the process of energy transfer between two groups of particles both processes operate simultaneously, and if the lower energy part of plasma distribution gives energy to the wave while the higher‐energy part absorbs the wave enrgy, then the wave‐mediated energy transfer from lower energy particles to higher‐energy ...

5 0
3 years ago
On the basis of which property of the elements are they divided in metals and non metals?​
kifflom [539]

Answer:

There are many properties that differentiate metals from non-metals. They are: Luster, conductivity of heat and electricity, physical strength i.e. Brittle or difficult to break, etc.

6 0
3 years ago
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