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Anastasy [175]
3 years ago
14

What is the formula of the ion formed when cadmium achieves a pseudo-noble-gas electron configuration? consult the periodic tabl

e. cd2- cd+ cd3+ cd2+?
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
The correct option is "Cd²⁺".

When an element achieves pseudo noble gas configuration<span> it means it has 18 </span>electrons<span> in the highest energy level instead of 8.

The electronic configuration of cadmium is:
</span><span>1<span>s</span></span>² <span>2<span>s</span></span>² <span>2<span>p</span></span>⁶ <span>3<span>s</span></span>² <span>3<span>p</span></span>⁶ <span>4<span>s</span></span>² <span>3<span>d</span></span>¹⁰ <span>4<span>p</span></span>⁶ <span>5<span>s</span></span>² <span>4<span>d<span>1</span></span></span>¹⁰<span><span><span>
</span></span></span>

and the electron configuration of <span>C<span>d</span></span>²⁺ is

<span>1<span>s</span></span>² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

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In standardizing a naoh solution a student found that 25.55cm of base neutralize exactly 21.35cm of 0.12M HCl find the molarity
nalin [4]

Answer:

O.1M

Explanation:

First let's generate a balanced equation for the reaction

NaOH + HCl —>NaCl + H2O

From the equation,

The ratio of the acid to base is 1:1.

From the question, we obtained the following:

Ma = Molarity of acid = 0.12M

Va = volume of acid = 21.35cm3

Vb = volume of base = 25.55cm3

Mb = Molarity of base =?

We obtained nA(mole of acid) and nB(mole of base) to be 1

The molarity of the base can be calculated for using:

MaVa/ MbVb = nA / nB

0.12x21.35 / Mb x 25.55 = 1

Cross multiply to express in linear form

Mb x 25.55 = 0.12x21.35

Divide both side by 25.55

Mb = (0.12x21.35) / 25.55

Mb = 0.1M

The molarity of the base is 0.1M

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horrorfan [7]

Answer:

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Read 2 more answers
the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.
trapecia [35]

The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

[Kr] 4d10 5s2 5p3

B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

[Xe] 6s1

Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

learn more about Noble gas:

brainly.com/question/2094768

#SPJ4

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Answer:

newtons 3rd law of motion

Explanation:

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What parts are present in every chemical equation?
77julia77 [94]
I believe it’s

The reactants

The products

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