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leonid [27]
2 years ago
10

A given mass of air has a volume of 8.00 L at 60.0°C. At constant pressure, the temperature is increased to 80.0°C. Calculate th

e final volume for the gas.​

Chemistry
1 answer:
AleksandrR [38]2 years ago
5 0

Answer:

D. 6.00 L

Explanation:

What we have here is an example of Boyle's Law. The equation here is P₁ · V₁ = P₂ · V₂. We know all of the values except for V₂.

60(8) = 80V

<em>Multiply 60 by 8 to get 480.</em>

480 = 80V

<em>Divide both sides by 80.</em>

480/80 = V

6 = V

The final volume for the gas is 6.00 L.

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A .......... notifies you that danger is present if the directions are not followed.
maksim [4K]

Answer:

A. Warning

Explanation:

Out of all said choices, the best choice would be warning since it would fit the sentence the most.

"A Warning notifies you that danger is present." compared to:

"A Hazard notifies you that danger is present."

"A Safety notifies you that danger is present."

"A Danger notifies you that danger is present."

5 0
2 years ago
To a 0.0001 m solution of mg(no3)2, naoh was added to a final concentration of 0.001m did a precipitate form?
Natalija [7]

I looked on a solubility chart to answer this question, and hydroxides are generally insoluble (with some exceptions of course). However, it says to consider Mg(OH)_{2} as an insoluble substance, though it may be moderately soluble.


The answer that you are most likely looking for is: Yes, a precipitate does form - this is due to the double placement reaction:


Mg(NO_{3})_{2}_{(aq)} + 2NaOH_{(aq)} → Mg(OH)_{2} {(s)} + 2NaNO_{3}_{(aq)}

8 0
3 years ago
PLEASE HELP!! GIVING BRAINLIEST
RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

Mass (M) = 1.60 \times  10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) =  ?

Formula:

\to \bold{V = \frac{M}{D}}

       = \frac{1.60 \times  10^{-3}}{9.293 \times  10^{-1}} \\\\  = \frac{1.60 \times  10^{1}}{9.293 \times  10^{3}} \\\\ = \frac{1.60 \times  10}{9.293 \times  1000} \\\\ = \frac{1.60 }{9.293 \times  100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603

4 0
3 years ago
Jelaskan perbedaan asam lemah dan asam kuat menurut teori arrhenius
AleksandrR [38]

<span>Explain the difference between a weak acid and a strong acid according to the Arrhenius theory his question in english</span>
6 0
3 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
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