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zalisa [80]
3 years ago
5

Which of the following is an example of static friction?

Physics
1 answer:
Tema [17]3 years ago
5 0
The answer is A.......
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The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an
Marrrta [24]

Answer:k=55.590 KN/m

Explanation:

Given

mass of person\left ( m\right )=68 kg

car dips about 1.2 cm

We know

F=kx

Where k=combined  spring constant

mg=kx

k=\frac{mg}{x}

k=\frac{68\times 9.81}{1.2\time 10^{-2}}

k=55.590 KN/m

7 0
3 years ago
Explain why the total positive charge in every atom of an element is always the<br> same.
geniusboy [140]

Answer:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.

Explanation:

3 0
2 years ago
Read 2 more answers
A 5.22×104 kg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constan
In-s [12.5K]

To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

\text{Initial Energy}=\text{Final Energy}

\frac{1}{2} mv^2=\frac{1}{2} kx^2

Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

mv^2 = kx^2

v^2 = \frac{kx^2}{m}

v = \sqrt{\frac{kx^2}{m}}

Our values are,

m = 5.22*10^4kg

k = 4.58*10^5N/m

x = 32cm = 0.32m

Replacing our values we have,

v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}

v = 2.733*10^5m/s

Therefore the velocity is 2.733*10^5m/s

8 0
3 years ago
2. Jak myślisz, dlaczego w naszym słowniku bez problemu odnajdziemy następujące wyrażenia
Juliette [100K]

Answer:

..........,

Explanation:

6 0
3 years ago
Which letter represents the position of maximum potential energy of the pendulum
worty [1.4K]
If you mean the SI Unit of GPE, the answer is J for Joules.
if that's not the question being asked, i would need a little more elaboration please :)
4 0
3 years ago
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