Which of the following is an example of static friction?

Tomorrow i have a science test, could someone please fill me in on the water cycle?

Lorico [155]

the cycle of processes by which water circulates between the earth's oceans, atmosphere and land involving precipitation as rain and snow drainage in streams and rivers and return to the atmosphere by evaporation and transpiration.

Hope this gives you a little bit more information!

5 0

3 years ago

Playing tetherball, a boy hits the 0.45 kg ball, moving toward him initially at 4.6 m/s, in the opposite direction at 2.5 m/s. H

saul85 [17]

Answer:

HI

Explanation:

8 0

2 years ago

Marvin Martian is standing on planet Potatoine.

prisoha [69]

Answer:

W = 113.98 N

Explanation:

Given that,

Radius of Potatoine $R=6.4\times 10^6\ m$

Mass of Potatoine, $M=2\times 10^{24}\ kg$

Mass of Marvin, m = 35 kg

We need to find his weight on Potatoine. Weight of an object is given by :

W = mg

g is acceleration due to gravity, $g=\dfrac{GM}{R^2}$

So,

$W=\dfrac{GMm}{R^2}\\\\W=\dfrac{6.67\times 10^{-11}\times 35\times 2\times 10^{24}}{(6.4\times 10^6)^2}\\\\W=113.98\ N$

So, his weight on Potatoine is 113.98 N.

4 0

2 years ago

The frequency of a wave is the inverse of the wave's<br> wavelength<br> itude<br> perod<br> velocit

zimovet [89]

The answer is period I think

8 0

2 years ago

Assume that you can heat water with perfect insulation (all the heat from combustion of ethanol is transferred to water). What i

krok68 [10]

Answer:

volumme =0.36 ml

Explanation:

total heat required can be obtained by using following formula

$q= mC \Delta T$ .......(1)

where,

m - mass of water,

C - specific heat capacity of water and = 4.184 j g^{-1} °C

$\Delta T$ - total change in temperature. = 10°C

The density of water is 1 g/cc. hence, 200 mL of water is equal to 200 g

putting all value in the above equation (1)

q = 200*4.184* 10 ° = 8368 J.

Therefore total number of moles of ethanol required to supply 8368 J of heat is

$\frac {8368}{1368000} = 0.006117 moles.$

The molar mass of ethanol is 46 g/mol.

The mass of ethanol required is 46* 0.006117 = 0.28138 g

The density of ethanol is 0.78 g/ml.

The volume of ethanol required is

$\frac {0.28138}{0.78} = 0.36 ml$

8 0

2 years ago