Explanation:
In this case we need to say that out of the attached figure which shows that the object is in uniform circular motion.
When and object moves in a circular path, its motion is called circular motion. In this type of motion, the speed of the object remains constant while its position changes i.e. its velocity changes.
Out of attached options, V shows circular motion, as the object is position continuously. W and Y are similar cases.
So, V, X and Y shows the circular motion of the object. Hence, this is the required solution.
Answer with Explanation:
We are given that
Weight of an ore sample=17.5 N
Tension in the cord=11.2 N
We have to find the total volume and the density of the sample.
We know that
Tension, T=
=buoyancy force
T=Tension force
W=Weight
By using the formula
N
Where
=Volume of object
=Density of water
=Acceleration due to gravity
Substitute the values then we get
Volume of sample=
Density of sample,
Where mass of ore sample=1.79 kg
Substitute the values then, we get
Density of the sample=
The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
#SPJ4
Answer:
The induced emf between two end is V
Explanation:
Given:
Length of rod m
Height m
Magnetic field T
For finding induced emf,
Where velocity of rod,
For finding the velocity of rod.
From kinematics equation,
Where initial velocity,
Put the velocity in above equation,
V
Therefore, the induced emf between two end is V