Transpiration is the process by which plants can have a controlled release of water through the stomata (openings) in their leaves. To release more water to the air, the guard cells separate and create the stomal openings. Hope this helps! :)
The design of rutherfords experiment show what he was trying to find out is by detect charged particles. He shot positively charged alpha particles at foil containing gold atoms, what they did showed what was in them neutrons etc Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Well, Bianca, I'll tell ya. You really haven't told us enough to completely define exactly what's going on here. In fact, now that I look at it carefully, you've told us nothing at all ... only asked a question based on zero given information.
IF you're talking about an object like a baseball or a rock or another projectile of some kind, and IF the object has no jet engines on it, and IF it has been tossed, launched, thrown, or otherwise sent on its way to somewhere other than the place it left from, and IF it's OK to ignore the effects of air resistance, then ...
-- the only force acting on the object is the force of gravity
-- gravity only points down
-- gravity has no effect on horizontal velocity
-- horizontal velocity is <em>constant</em>, and <em>doesn't change </em>as time goes on.
But IF any of these things is different, then you can forget everything I said. I'm just guessing.
Answer:
The velocity is ![v = 2.6*10^{8} \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%202.6%2A10%5E%7B8%7D%20%5C%20m%2Fs)
Explanation:
From the question we are told that
The side of the cube is ![l = 0.13 \ m](https://tex.z-dn.net/?f=l%20%3D%20%200.13%20%5C%20m)
The mass of the object is ![m = 2.0 \ kg](https://tex.z-dn.net/?f=m%20%20%3D%20%202.0%20%5C%20kg)
The density of the object is ![\rho = 7300 \ kg / m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%20%207300%20%5C%20%20kg%20%2F%20m%5E3)
Generally the volume of the object according to the moving observer is mathematically represented as
![V =\frac{m}{\rho}](https://tex.z-dn.net/?f=V%20%20%3D%5Cfrac%7Bm%7D%7B%5Crho%7D)
![V =\frac{2}{7300}](https://tex.z-dn.net/?f=V%20%20%3D%5Cfrac%7B2%7D%7B7300%7D)
![V = 2.74*10^{-4} \ m^3](https://tex.z-dn.net/?f=V%20%20%3D%20%202.74%2A10%5E%7B-4%7D%20%5C%20m%5E3)
Therefore the length of the side as observed by the observer on high speed is mathematically represented as
![L =0.065](https://tex.z-dn.net/?f=L%20%3D0.065)
Now the original length of side is mathematically represented as
![L= l * \sqrt{ (1 - ( \frac{ v}{c})^2 )}](https://tex.z-dn.net/?f=L%3D%20%20l%20%20%2A%20%20%5Csqrt%7B%20%281%20-%20%28%20%5Cfrac%7B%20v%7D%7Bc%7D%29%5E2%20%29%7D)
Where c is the speed of light with value ![c = 3.0*10^{8} \ m/s](https://tex.z-dn.net/?f=c%20%3D%20%203.0%2A10%5E%7B8%7D%20%5C%20%20m%2Fs)
So
![v = \sqrt{1 - [\frac{L}{l}]^2} * c](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B1%20-%20%5B%5Cfrac%7BL%7D%7Bl%7D%5D%5E2%7D%20%2A%20%20c)
=> ![v = \sqrt{1 - [\frac{0.065}{0.13}]^2} * c](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B1%20-%20%5B%5Cfrac%7B0.065%7D%7B0.13%7D%5D%5E2%7D%20%2A%20%20c)
=> ![v = 2.6*10^{8} \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%202.6%2A10%5E%7B8%7D%20%5C%20m%2Fs)
Answer:
The maximum temperature rise = 0.047 °C
Explanation:
Potential Energy, P = mgh
Energy transfered, Q=mcΔT
Potential energy = Energy transfered
mgh = mcΔT
gh = cΔT
ΔT = gh/c
ΔT = (9.81 * 20) / 4186
ΔT = 0.047 °C