Cubic centimeters for the volume of a solid.
Liters for volume of a liquid.
Clues or evidence
Im pretty sure its evidence though
Answer:
0.4778 m/s
Explanation:
To solve this question, we will make use of law of conservation of momentum.
We are given that the rock's velocity is 12 m/s at 35°. Thus, the horizontal component of this velocity is;
V_x = (12 m/s)(cos(35°)) = 9.83 m/s.
Thus, the horizontal component of the rock's momentum is;
(3.5 kg)(9.83 m/s) = 34.405 kg·m/s.
Since the person is not pushed up off the ice or down into it, his momentum will have no vertical component and so his momentum will have the same magnitude as the horizontal component of the rock's momentum.
Thus, to get the person's speed, we know that; momentum = mass x velocity
Mass of person = 72 kg and we have momentum as 34.405 kg·m/s
Thus;
34.405 = 72 x velocity
Velocity = 34.405/72
Velocity = 0.4778 m/s
We have
y=78.4 m and the distance, x=2400 m
we need to find out the time in the air, t=√2y/a
where a is 9.8 m/s²
t=√ 2*(-78.4)/-9.8 m/s²= √ -156.80/ -9.8 =√16=4s
speed of the bullet will be
v=x/t= 2400/4= 600m/s
Answer:
a) = 72.75 kg
, b) V = 0.07275 m³
, c) ρ₂ = 1030.9 km / m³
, d) ρ₂= 996 kg / m³ float
Explanation:
This is an exercise that we must solve using the Archimedes principle, where the thrust is
B = ρ g V
a) Let's use Newton's second law
F = B - W
F = ρ g V - mg
The force is the apparent weight (m₂ = 2.25 kg) is directed downwards so it is negative
F = m₂ g
-m₂ g = ρ g V - m g
-m₂ g = g - mg
= -m₂ + m
= -2.25 + 75.0
= 72.75 kg
b) let's use the definition of density
ρ = m / V
V = m /ρ
V = 72.75 / 1000
V = 0.07275 m³
c) the density of man is
ρ₂ = m / V
ρ₂ = 75.0 / 0.07275
ρ₂ = 1030.9 km / m³
d) the volume of man increases because the lungs are full of air, as they are half full, with a capacity of 2.5 liters and two lungs the volume is
V’= ½ 2.5 2
V’= 2.5 liters
V’= 2.5 10⁻³ m³
The total volume of man is
Vt = 0.07275 + 0.0025
Vt = 0.07525
Let's calculate the density
ρ₂ = 75.0 / 0.07525
ρ₂= 996 kg / m³
As this is less than the density of water (1000 kg / m3) man must float