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3 years ago

What are some examples of transverse waves?

Physics

1 answer:

Deffense [45]3 years ago

7 0

Answer:

-ripples on the surface of water.

-vibrations in a guitar string.

-a Mexican wave in a sports stadium.

-electromagnetic waves – eg light waves, microwaves, radio waves.

-seismic S-waves.

Explanation:

I've done this question before

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A 6V radio with a current of 2A is turned on for 5 minutes. Calculate the energy transferred in joules

iogann1982 [59]

Answer:

R=V/I=6/2=3ohm

time =5minutes =5*60=300seconds

I=2A

Heat =I^2Rt=(2)^2*3*300=4*900=3600J

7 0

2 years ago

A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a

AlekseyPX

Answer:

Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day

Part (b) The specific discharge of the flow is 0.0363 m/day

Part (c) The average linear velocity of the flow is 0.242 m/day

Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours

Explanation:

Part (a) the flow rate per unit width of the aquifer

From Darcy's law;

$q = -Kb\frac{dh}{dl}$

where;

q is the flow rate

K is the permeability or conductivity of the aquifer = 25 m/day

b is the aquifer thickness

dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m

dl is the change in the horizontal hight = 1000 m

q = -(25*30)*(-1.45/1000)

q = 1.0875 m³/day

Part (b) the specific discharge of the flow

$V = \frac{Q}{A} = \frac{q}{b} = -K\frac{dh}{dl}\\\\V = -(25 m/d).(\frac{-1.45 m}{1000 m}) = 0.0363 m/day$

V = 0.0363 m/day

Part (c) the average linear velocity of the flow assuming steady unidirectional flow

Va = V/Φ

Φ is the porosity = 0.15

Va = 0.0363 / 0.15

Va = 0.242 m/day

Part (d) the time taken for a tracer to travel the distance between the observation wells

The distance between the two wells = 1000 m

average linear velocity = 0.242 m/day

Time = distance / speed

Time = (1000 m) / (0.242 m/day)

Time = 4132.23 days

$= 4132.23 days *\frac{24 .hrs}{1.day} = 99173.52, hours$

4 0

3 years ago

Amber asked her roommate to turn down the radio because she was trying to study. Her roommate had increased the volume from a vo

Blizzard [7]

Answer:

Difference threshold or also Just Noticeable Difference

Explanation:

The above mentioned case between room mates, where one room mate was able to detect a minute change in volume shows an instance of the difference threshold.

Difference threshold can be defined as stimulation at its minimum level that can be detected by an individual almost 50 % of the times.

It is the lowest possible level of sound that is detectable by a person.

That is what happened in the mentioned case that when the volume was increased from 14 to 15, Amber was able to detect it.

7 0

3 years ago

A 5.0 kg object moving at 10 m/s on a frictionless surfaces collides with but does not stick to a 2.0 kg object that is initiall

lilavasa [31]

Answer:

I= 20 i {N.s}

Explanation:

In order to obtain the impulse on the 2 kg ball, you have to apply the equation of Impulse:

I=FΔt

Where I is the impulse vector, F is the net force and Δt is the interval of time when the force is applied.

In this case:

Δt=0.01 s

F= 2000 i N

where i is the unit vector in the x direction.

Replacing the values in the formula:

I=(2000)(0.01)i

Therefore:

I= 20 i {N.s}

3 0

3 years ago

I Science Sem 1

Sonbull [250]

Answer:

Force, F = 124 N

Explanation:

We have,

Mass of bicycle is 12 kg and mass of rider is 50 kg

Total mass of the system is 12 kg + 50 kg = 62 kg

Acceleration of the system is 2 m/s²

It is required to find the force required to accelerate the system. The force acting on an object is given by :

$F=ma\\\\F=62\ kg\times 2\ m/s^2\\\\F=124\ N$

So, the force of 124 N is acting on the system.

7 0

3 years ago